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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ? [#permalink]
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Kritesh wrote:
For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?\)

(A) \(–4x^2 – 18xy – 16y^2\)

(B) \(–4x^2 + 6xy – 16y^2\)

(C) \(–4x^2 + 6xy – 8y^2\)

(D) \(4x^2 – 6xy + 16y^2\)

(E) \(12x^2 – 18xy – 8y^2\)


4^x - 6xy - 12y^2 - (8x^2 - 12xy + 4y^2)

4^x - 6xy - 12y^2 - 8x^2 + 12xy - 4y^2

-4x^2 + 6xy - 16y^2

Answer: B
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For all x and y, (4x^2 -6xy - 12y^2) - (8x^2 -12xy + 4y^2) = [#permalink]
Bunuel wrote:
For all x and y, \((4x^2 -6xy - 12y^2) - (8x^2 -12xy + 4y^2) =\)


(A) \(-4x^2 - 18xy - 16y^2\)

(B) \(-4x^2 + 6xy - 16y^2\)

(C) \(-4x^2 - 6xy + 8y^2\)

(D) \(4x^2 - 6xy + 16y^2\)

(E) \(12x^2 - 18xy - 8y^2\)


solve expression
we would get
\(-4x^2 + 6xy - 16y^2\)
IMO B

Originally posted by Archit3110 on 11 Feb 2019, 02:03.
Last edited by Archit3110 on 12 Feb 2019, 04:14, edited 1 time in total.
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For all x and y, (4x^2 -6xy - 12y^2) - (8x^2 -12xy + 4y^2) = [#permalink]
For all x and y, (4x^2 -6xy - 12y^2) - (8x^2 -12xy + 4y^2) =

4x^2 -6xy - 12y^2 -8x^2 +12xy - 4y^2 = -->minus sign applies to all the 2nd parentheses.

4x^2 -8x^2 -6xy +12xy - 12y^2 - 4y^2 = -->solve

-4x^2 +6xy - 16y^2 --> I think it's answer B
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ? [#permalink]
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ? [#permalink]
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