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# For any a and b that satisfy |a – b| = b – a and a > 0, then |a + 3| +

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Joined: 21 Jun 2017
Posts: 70

Kudos [?]: 4 [0], given: 2

Re: For any a and b that satisfy |a – b| = b – a and a > 0, then |a + 3| + [#permalink]

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13 Oct 2017, 09:41
Bunuel wrote:
For any a and b that satisfy $$|a – b| = b – a$$ and $$a > 0$$, then $$|a + 3| + |-b| + |b – a| + |ab| =$$

A. $$-ab + 3$$

B. $$ab + 3$$

C. $$-ab + 2b + 3$$

D. $$ab + 2b – 2a – 3$$

E. $$ab + 2b + 3$$

Kudos for a correct solution.

Given |a-b| = b - a
b>a, for |a-b| = positive
a>0
therefore, a+3>0

Let a = 1, b=2
4+ 2 + 1 + 2 = 9
ab + 2b + 3 = 2+4+3 = 9

Therefore, (E) ab + 2b + 3

Kudos [?]: 4 [0], given: 2

Re: For any a and b that satisfy |a – b| = b – a and a > 0, then |a + 3| +   [#permalink] 13 Oct 2017, 09:41

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