Bunuel wrote:

For any positive integer x, the 2-height of x is defined to be the greatest nonnegative integer n such that 2^n is a factor of x. If k and m are positive integers, is the 2-height of k greater than the 2-height of m?

(1) k > m

(2) k/m is an even integer.

Kudos for a correct solution.

chetan2u wrote:

Cheryn wrote:

0 is also even integer, so what if k/m is 0?

Hi, always read the entire q thoroughly so as not to miss out on minor details.

It is given m and k are positive integers so they cannot be 0

Bunuel chetan2uI think

Cheryn means that the ratio k/m can be equal to 0. If that's the case, then B would be insufficient. I don't any condition given in the question stem that does not allow m to be equal to n. Please let me know if I'm missing something. Thanks!

For example:

Case 1: No

k = m = 3

2-height of k greater = 2-height of m greater = 0

Case 2: Yes

k = 6, m = 3

(2-height of k greater = 1) > (2-height of m greater = 0)

For stmt 1+2, from stmt 1 we have k>m so case 1 from stmt 2 is not valid. Hence the answer is C.

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