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Re: For how many integers, denoted by "q", is
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15 Mar 2018, 23:37
1
rishabhmishra wrote:
For how many integers, denoted by "q", is \(2^{[q]} =q^2\)? A. ONE B. TWO C. THREE D. FOUR E. MORE THAN FOUR.
This is possible for 4 integers 2, 4, -2 and -4 as \(2^4\) = 16 \(4^2\)=16 \(2^2\)= 4 and for - from the equation above those negative will converted into + by squaring or by [q]
Re: For how many integers, denoted by "q", is
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28 Mar 2018, 11:20
1
Hi, I have a discrepancy with the answer and approach to the solution, it is not mentioned that [q] is absolute value of q, generally |q| is taken to be so. Also, in many cases the square brackets are used for greatest or smallest integer above or below a value type of questions, or it could simply mean square brackets. So i believe it is necessary for the symbol to be expressed correctly. Please correct me if I am wrong.
Re: For how many integers, denoted by "q", is
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28 Mar 2018, 19:49
ShriyaMisra wrote:
Hi, I have a discrepancy with the answer and approach to the solution, it is not mentioned that [q] is absolute value of q, generally |q| is taken to be so. Also, in many cases the square brackets are used for greatest or smallest integer above or below a value type of questions, or it could simply mean square brackets. So i believe it is necessary for the symbol to be expressed correctly. Please correct me if I am wrong.
You are right. If it's meant to be the absolute value of q, then it should have been written as |q| NOT [q]. Edited.
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