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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?

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V
Joined: 02 Sep 2009
Posts: 53657
For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 11 Apr 2017, 01:29
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

64% (01:39) correct 36% (01:40) wrong based on 156 sessions

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S
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Joined: 25 Jan 2016
Posts: 130
Location: India
Concentration: Finance, Entrepreneurship
GPA: 4
WE: Web Development (Computer Software)
Re: For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 11 Apr 2017, 08:16
1
answer is C

for x=1 and x=2 value is 1 so combining we can solve the question
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 16 Jan 2019, 06:51
\(\frac{4}{5}^x + \frac{3}{5}^x < 1\)

Now, when x<0 this might not be true, hence we need both statements
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?   [#permalink] 16 Jan 2019, 06:51
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?

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