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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?

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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 11 Apr 2017, 01:29
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A
B
C
D
E

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  45% (medium)

Question Stats:

63% (01:38) correct 37% (01:39) wrong based on 150 sessions

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Re: For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 11 Apr 2017, 08:16
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answer is C

for x=1 and x=2 value is 1 so combining we can solve the question
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 16 Jan 2019, 06:51
\(\frac{4}{5}^x + \frac{3}{5}^x < 1\)

Now, when x<0 this might not be true, hence we need both statements
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Re: For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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New post 27 Mar 2019, 02:11
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ghnlrug wrote:
\(\frac{4}{5}^x + \frac{3}{5}^x < 1\)

Now, when x<0 this might not be true, hence we need both statements



X is non-negative per question statement
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Re: For non-negative x and y, is (0.8)^x+(0.6)^x<y ?   [#permalink] 27 Mar 2019, 02:11
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?

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