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# For non-negative x and y, is (0.8)^x+(0.6)^x<y ?

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Math Expert
Joined: 02 Sep 2009
Posts: 53657
For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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11 Apr 2017, 01:29
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Difficulty:

45% (medium)

Question Stats:

64% (01:39) correct 36% (01:40) wrong based on 156 sessions

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For non-negative x and y, is $$(0.8)^x+(0.6)^x<y$$ ?

(1) y ≥ 1

(2) x ≥ 3

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Joined: 25 Jan 2016
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Location: India
Concentration: Finance, Entrepreneurship
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Re: For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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11 Apr 2017, 08:16
1

for x=1 and x=2 value is 1 so combining we can solve the question
Manager
Joined: 03 Sep 2018
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?  [#permalink]

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16 Jan 2019, 06:51
$$\frac{4}{5}^x + \frac{3}{5}^x < 1$$

Now, when x<0 this might not be true, hence we need both statements
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For non-negative x and y, is (0.8)^x+(0.6)^x<y ?   [#permalink] 16 Jan 2019, 06:51
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