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For positive integer k, is the expression (k + 2)(k^2 + 4k +

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Intern
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Joined: 18 Aug 2017
Posts: 30
GMAT 1: 670 Q49 V33
Re: For positive integer k, is the expression (k + 2)(k^2 + 4k + [#permalink]

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New post 25 Aug 2017, 21:03
One way to look at statement 1 using divisibility rule:

k is divisible by 8
so k is divisible by 4
k+1 :4 gives remainder of 1
k+2 :4 gives remainder of 2
k+3 :4 gives remainder of 3

None of the factor in the product (k+1)(k+2)(k+3) is divisible by 4, therefore the product is not divisible by 4.
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Re: For positive integer k, is the expression (k + 2)(k^2 + 4k + [#permalink]

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New post 30 Dec 2017, 06:11
[quote="Bunuel"]


- Doubt

Since k is +ve => min value of k+1 = 2, hence series can be (2,3,4), (3,4,5), (4,5,6) => product is always divisible by 4 ?
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Re: For positive integer k, is the expression (k + 2)(k^2 + 4k + [#permalink]

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New post 30 Dec 2017, 06:16
Re: For positive integer k, is the expression (k + 2)(k^2 + 4k +   [#permalink] 30 Dec 2017, 06:16

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