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For the past x laps around the track, Steven’s average time per lap

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For the past x laps around the track, Steven’s average time per lap  [#permalink]

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New post 14 Oct 2017, 06:35
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  25% (medium)

Question Stats:

79% (01:41) correct 21% (02:16) wrong based on 67 sessions

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For the past x laps around the track, Steven’s average time per lap  [#permalink]

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New post 14 Oct 2017, 06:41
Bunuel wrote:
For the past x laps around the track, Steven’s average time per lap was 51 seconds. If a lap of 39 seconds would reduce his average time per lap to 49 seconds, what is the value of x?

(A) 2
(B) 5
(C) 6
(D) 10
(E) 12


Total time for \(x\) laps \(= 51*x\)

total time after additional lap of \(39\) sec \(= 49*(x+1)\)

therefore \(51x+39=49(1+x)\)

or \(x=5\)

Option B
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For the past x laps around the track, Steven’s average time per lap  [#permalink]

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New post 14 Oct 2017, 06:54
Bunuel wrote:
For the past x laps around the track, Steven’s average time per lap was 51 seconds. If a lap of 39 seconds would reduce his average time per lap to 49 seconds, what is the value of x?

(A) 2
(B) 5
(C) 6
(D) 10
(E) 12

A* n = S

First x laps: 51 * x
Extra lap : 39 * 1
Sum: 51x + 39
Total number n of laps: x + 1

A = S/n, where A = 49

\(\frac{(51x+39)}{(x+1)} = 49\)

\((51x+39)= 49(x+1)\)

\(51x+39= 49x+49\)

\(2x = 10\)

\(x = 5\)

Answer B
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Re: For the past x laps around a track, Stevens avergae time per  [#permalink]

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New post 30 Mar 2019, 21:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: For the past x laps around a track, Stevens avergae time per   [#permalink] 30 Mar 2019, 21:55
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