GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 15 Oct 2019, 02:35

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

For the past x laps around the track, Steven’s average time per lap

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58355
For the past x laps around the track, Steven’s average time per lap  [#permalink]

Show Tags

New post 14 Oct 2017, 06:35
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

82% (01:38) correct 18% (02:16) wrong based on 76 sessions

HideShow timer Statistics

Retired Moderator
avatar
D
Joined: 25 Feb 2013
Posts: 1179
Location: India
GPA: 3.82
GMAT ToolKit User Reviews Badge
For the past x laps around the track, Steven’s average time per lap  [#permalink]

Show Tags

New post 14 Oct 2017, 06:41
Bunuel wrote:
For the past x laps around the track, Steven’s average time per lap was 51 seconds. If a lap of 39 seconds would reduce his average time per lap to 49 seconds, what is the value of x?

(A) 2
(B) 5
(C) 6
(D) 10
(E) 12


Total time for \(x\) laps \(= 51*x\)

total time after additional lap of \(39\) sec \(= 49*(x+1)\)

therefore \(51x+39=49(1+x)\)

or \(x=5\)

Option B
Senior SC Moderator
avatar
V
Joined: 22 May 2016
Posts: 3538
For the past x laps around the track, Steven’s average time per lap  [#permalink]

Show Tags

New post 14 Oct 2017, 06:54
Bunuel wrote:
For the past x laps around the track, Steven’s average time per lap was 51 seconds. If a lap of 39 seconds would reduce his average time per lap to 49 seconds, what is the value of x?

(A) 2
(B) 5
(C) 6
(D) 10
(E) 12

A* n = S

First x laps: 51 * x
Extra lap : 39 * 1
Sum: 51x + 39
Total number n of laps: x + 1

A = S/n, where A = 49

\(\frac{(51x+39)}{(x+1)} = 49\)

\((51x+39)= 49(x+1)\)

\(51x+39= 49x+49\)

\(2x = 10\)

\(x = 5\)

Answer B
_________________
SC Butler has resumed! Get two SC questions to practice, whose links you can find by date, here.




Choose life.
Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 13146
Re: For the past x laps around a track, Stevens avergae time per  [#permalink]

Show Tags

New post 30 Mar 2019, 21:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Bot
Re: For the past x laps around a track, Stevens avergae time per   [#permalink] 30 Mar 2019, 21:55
Display posts from previous: Sort by

For the past x laps around the track, Steven’s average time per lap

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne