hazelnut wrote:

For the rectangular shown above, if \((BR)=(BQ)=5\sqrt{2}\) and \((AR)=(PB)=(CQ)=\sqrt{119}\), what is the area of the triangle PQR?

A. 30

B. 45

C. 60

D. 75

E. 90

QR = \(\sqrt{{{5[square_root]2}}^2 + {5\sqrt{2}}^2}[/square_root]\) = 10

PQ = PR = \(\sqrt{{{[square_root]119}}^2 + {5\sqrt{2}}^2}[/square_root][/square_root]\) = 13

So,, sides of triangle are 13,13,10

semi perimeter = (13+13+10)/2= 18

Area of triangle PQR = \(\sqrt{18*(18-13)*(18-13)*(18-10)}\) = 60.

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