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# for what value(s) of m will the equation have = roots (3m +

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Director
Joined: 07 Jun 2004
Posts: 612
Location: PA
for what value(s) of m will the equation have = roots (3m + [#permalink]

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10 Jan 2005, 16:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

for what value(s) of m will the equation have = roots

(3m + 1) X^2 + 2(m+1)X + m = 0
Intern
Joined: 08 Jan 2005
Posts: 6

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10 Jan 2005, 17:04
hmm " = roots " .. u mean have equal roots ? or is it that the equation will have non imaginary roots ...

I think if we take it as equal roots..
then m = -1/2 and 1
Director
Joined: 07 Jun 2004
Posts: 612
Location: PA

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10 Jan 2005, 17:09
Senior Manager
Joined: 03 Nov 2004
Posts: 485

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11 Jan 2005, 23:01
maybe i am not undestanding the quesiton, but can any of you guys explain the answer. are there any answer choices ???
VP
Joined: 25 Nov 2004
Posts: 1483

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12 Jan 2005, 00:07
Good question. m = 1.

suppose m=1 and replace m with 1 in the given eq,

4X^2 + 4X + 1 = 0

solving the eq, x = -1/2 or roots of the eq is -1/2.
Director
Joined: 19 Nov 2004
Posts: 556
Location: SF Bay Area, USA

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12 Jan 2005, 00:17
(3m + 1) X^2 + 2(m+1)X + m = 0
is a quadratic equation of form aX^2 + bX + c

The roots of this equation are equal if b^2 - 4*a*c = 0

=> Roots are equal if (2(m+1))^2 - 4*(3m+1)(m) = 0

Solve for m , you get the answers
12 Jan 2005, 00:17
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