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# For which of the following lists, the mean is greater than the median?

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General GMAT Forum Moderator
Joined: 29 Jan 2015
Posts: 1252
Location: India
WE: General Management (Non-Profit and Government)
For which of the following lists, the mean is greater than the median?  [#permalink]

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14 Apr 2019, 06:04
1
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Difficulty:

85% (hard)

Question Stats:

29% (02:38) correct 71% (02:07) wrong based on 24 sessions

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For which of the following lists, the mean is greater than the median?

I. 2/3, 3/4, 4/5, 5/6, 6/7

II. 8/7, 7/6, 6/5, 5/4, 4/3

III. 1/2, 1/3, 1/4, 1/5, 1/6

(A) I only

(B) II only

(C) III only

(D) I and II

(E) II and III

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Intern
Joined: 06 Apr 2019
Posts: 7
For which of the following lists, the mean is greater than the median?  [#permalink]

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18 Apr 2019, 15:40
I. 2/3, 3/4, 4/5, 5/6, 6/7 FALSE

$$\frac{0.75 + 0.83}{2} < 0.8$$

II. 8/7, 7/6, 6/5, 5/4, 4/3 TRUE

$$\frac{1.16 + 1.25}{2} > 1.20$$

III. 1/2, 1/3, 1/4, 1/5, 1/6 TRUE

$$\frac{0.33 + 0.2}{2} > 0.25$$

Since II and III are true, therefore the answer is (E)
Manager
Joined: 11 Jun 2018
Posts: 85
GMAT 1: 500 Q39 V21
Re: For which of the following lists, the mean is greater than the median?  [#permalink]

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01 May 2019, 09:46
chetan2u, VeritasKarishma, Gladiator59 :- is there a shortcut for these questions, without actually calculating?
Intern
Joined: 27 Nov 2018
Posts: 35
GMAT 1: 510 Q33 V28
Re: For which of the following lists, the mean is greater than the median?  [#permalink]

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01 May 2019, 10:49
danz1ka19 wrote:
I. 2/3, 3/4, 4/5, 5/6, 6/7 FALSE

$$\frac{0.75 + 0.83}{2} < 0.8$$

II. 8/7, 7/6, 6/5, 5/4, 4/3 TRUE

$$\frac{1.16 + 1.25}{2} > 1.20$$

III. 1/2, 1/3, 1/4, 1/5, 1/6 TRUE

$$\frac{0.33 + 0.2}{2} > 0.25$$

Since II and III are true, therefore the answer is (E)

Why u didnt take mean of all 05 numbers ? Like for all 05 fractions - 2/3, 3/4, 4/5, 5/6, 6/7
You took mean of only two numbers (one before and one after the median) $$\frac{0.75 + 0.83}{2}$$
Is thr some trick or concept ?
Re: For which of the following lists, the mean is greater than the median?   [#permalink] 01 May 2019, 10:49
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