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Forty applicants for a job had 252 years of experience between them.

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Forty applicants for a job had 252 years of experience between them. [#permalink]

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New post 27 Dec 2017, 00:02
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Forty applicants for a job had 252 years of experience between them. 13 had an average of 4 years of experience. Sixteen had an average of 7 years experience. What was the average (arithmetic mean) amount of experience of the rest of the applicants?

A. 6
B. 7.4
C. 8
D. 8.6
E. 9
[Reveal] Spoiler: OA

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Re: Forty applicants for a job had 252 years of experience between them. [#permalink]

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New post 27 Dec 2017, 00:27
Bunuel wrote:
Forty applicants for a job had 252 years of experience between them. 13 had an average of 4 years of experience. Sixteen had an average of 7 years experience. What was the average (arithmetic mean) amount of experience of the rest of the applicants?

A. 6
B. 7.4
C. 8
D. 8.6
E. 9


Since the answers are very close together we have no choice but to go for a straightforward calculation.
This is a Precise approach.

13*4 = 52 and 16*7 = 112
So 29 applicants had a total of 52+112=164 years of experience
The remaining 11 had a total of 252 - 164 =88 years of experience.
Then each had 88/11 = 8 years of experience on average.

(C) is our answer
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Re: Forty applicants for a job had 252 years of experience between them. [#permalink]

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New post 28 Dec 2017, 02:57
Bunuel wrote:
Forty applicants for a job had 252 years of experience between them. 13 had an average of 4 years of experience. Sixteen had an average of 7 years experience. What was the average (arithmetic mean) amount of experience of the rest of the applicants?

A. 6
B. 7.4
C. 8
D. 8.6
E. 9


\(Average=\frac{Total.Years}{Applicants}=\frac{252}{40}\)

\(\frac{252}{40}=\frac{(13*4)+(16*7)+(11*x)}{40}\), \(252=(52)+(112)+(11*x)\), \(\frac{252-(164)}{11}=x\), \(x=8\)

(C) is the answer.
Re: Forty applicants for a job had 252 years of experience between them.   [#permalink] 28 Dec 2017, 02:57
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Forty applicants for a job had 252 years of experience between them.

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