Four buses carry tourists, so that the number of tourists in the first

Let number of tourists in Bus 2 = 100

number of tourists in the first bus is 40 percent more than that in the second bus
--> Bus 1 = 140

number of tourists in the first bus is 30 percent less than that in the third bus
--> Number of tourists in Bus 1 = 70% of Bus 3
--> 70/100*(Bus 3) = 140
--> Bus 3 = 140*100/70 = 200

The fourth bus carries twice as many tourists as the second bus
--> Bus 4 = 2*100 = 200

{Bus 1, Bus 2, Bus 3, Bus 4} = {140, 100, 200, 200}
--> Mode = 200

Average = Total/4 = 640/4 = 160

The average (arithmetic mean) of the number of tourists in each bus is what percentage of the mode of these numbers
--> Average = x% of Mode
--> 160 = x/100*200
--> x = (160*100)/200 = 80

IMO Option E

Pls Hit Kudos if you like the solution