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Four female friends & four male friends will be pictured in

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Manager
Joined: 29 Nov 2011
Posts: 81

Kudos [?]: 382 [0], given: 37

Four female friends & four male friends will be pictured in [#permalink]

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05 Apr 2012, 01:30
00:00

Difficulty:

45% (medium)

Question Stats:

41% (00:47) correct 59% (01:19) wrong based on 17 sessions

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Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row, with men & women alternating. How many possible arrangements may she chose?

A. 40320
B. 1680
C. 1152
D. 576
E. 70
[Reveal] Spoiler: OA

Last edited by Bunuel on 05 Apr 2012, 03:59, edited 1 time in total.
Edited the question and added the OA

Kudos [?]: 382 [0], given: 37

Senior Manager
Joined: 13 Mar 2012
Posts: 351

Kudos [?]: 207 [0], given: 31

Concentration: Operations, Strategy

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05 Apr 2012, 01:58
Smita04 wrote:
Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row,with men & women alternating.How many possible arrangements may she chose?
A)40320
B)1680
C)1152
D)576
E)70

okay you got 2 ways of assigning alternate places to either male or female

hence 2

now any of the alternate 4 places can be filled by 4 male or female in 4!
similarily,
other 4 alternate places can be filled in 4!

hence required probability= 2*4!*4!=1152

hence C

Hope this helps..!!
_________________

Practice Practice and practice...!!

If there's a loophole in my analysis--> suggest measures to make it airtight.

Kudos [?]: 207 [0], given: 31

Math Expert
Joined: 02 Sep 2009
Posts: 42356

Kudos [?]: 133204 [0], given: 12439

Re: Four female friends & four male friends will be pictured in [#permalink]

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05 Apr 2012, 04:03
Smita04 wrote:
Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row, with men & women alternating. How many possible arrangements may she chose?

A. 40320
B. 1680
C. 1152
D. 576
E. 70

To meet the condition in the stem men and women should line up either: M-W-M-W-M-W-M-W or W-M-W-M-W-M-W-M. Now, for each of these two cases men can be arranged in 4! ways and women can be arranged also in 4! ways, hence total # of arrangements is 2*4!*4!=1,152.

Hope it's clear.
_________________

Kudos [?]: 133204 [0], given: 12439

Re: Four female friends & four male friends will be pictured in   [#permalink] 05 Apr 2012, 04:03
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