oli29 wrote:
Hey Guys,
How come that I can not just add all single possibilities of how the committee is structured e.g. (All Females) + (3 Females 1 Male) + (2 Females 2 Males) + (1 Female 3 Males):
n= 6C4 + (6C3 *6C1) + (6C2 * 6C2) + (6C1 * 6C3) ?
Hi
oli29,
Your method is perfectly fine. The above expression would give you the same result, but as you notice that the calculation becomes tedious.
There is a small trick to solve such problems: Use
Complementary Method.
Total number of ways to choose four representative = (4 Females, 0 Males) + (3 Females, 1 Male) + (2 Females, 2 Males) + (1 Female, 3 Males) + (0 Females, 4 Males).
Please note that required event = Total - (0 Females, 4 Males).
Please refer the post by
TheOutlawTorn.
Hope this helps.