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Four staff members at a certain company worked on a project.

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Senior Manager
Joined: 27 Aug 2007
Posts: 253

Kudos [?]: 12 [0], given: 0

Four staff members at a certain company worked on a project. [#permalink]

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17 Nov 2007, 06:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 30 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?

A. 80
B. 96
C. 160
D. 192
E. 240

Kudos [?]: 12 [0], given: 0

VP
Joined: 08 Jun 2005
Posts: 1144

Kudos [?]: 246 [0], given: 0

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17 Nov 2007, 07:30
2:3:5:6 = sum = 16

80/16 = 5

96/16 = 6

160/16 = 10

192/16 = 12

240/16 = 15

only 12 is not a multiply of 30 - so the ratio of 2:3:5:6 cannot be solved.

the answer is (D)

Kudos [?]: 246 [0], given: 0

Senior Manager
Joined: 27 Aug 2007
Posts: 253

Kudos [?]: 12 [0], given: 0

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17 Nov 2007, 07:46
KillerSquirrel wrote:
2:3:5:6 = sum = 16

80/16 = 5

96/16 = 6

160/16 = 10

192/16 = 12

240/16 = 15

only 12 is not a multiply of 30 - so the ratio of 2:3:5:6 cannot be solved.

the answer is (D)

NO words, clear and precise

Kudos [?]: 12 [0], given: 0

17 Nov 2007, 07:46
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Four staff members at a certain company worked on a project.

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