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# From a group of 3 boys and 3 girls , 4 children are to be

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From a group of 3 boys and 3 girls , 4 children are to be [#permalink]

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16 Aug 2004, 13:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

From a group of 3 boys and 3 girls , 4 children are to be randomly selected .
What is the probability that equal number of boys and girls will be selected?
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16 Aug 2004, 14:50
I would say

(3C2 * 3C2) / 6C4

= 4/15

the top is the number of ways you can select two of the 3 boys times the number of ways you can select 2 of the 3 girls

the bottom is the number of ways you can select 4 of the six children
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17 Aug 2004, 09:24
Agree. Same solution.
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17 Aug 2004, 10:13
Wouldn't the correct answer be 9/15? 3C2 =3*3=9
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17 Aug 2004, 10:27
Yup it's 9/15.
Sorry, I only checked SigEpUCI's way.
He made a little mistake in the final calculation.
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17 Aug 2004, 10:39
can someone please explain why is not (3c2 + 3c2) / 6C4
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17 Aug 2004, 10:46
Use + when you need an "OR", and use * when you need an "AND".
In this question for example, you pick 2 boys AND 2 girls.
That's why you have to multiply.
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17 Aug 2004, 10:48
damit wrote:
can someone please explain why is not (3c2 + 3c2) / 6C4

If I am not wrong, as we want 2 boys AND 2 girls, we multiply. Addition is for "OR". Somebody correct me if I am not right.
17 Aug 2004, 10:48
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