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# Fundamental probability question....

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Intern
Joined: 29 Jun 2004
Posts: 19
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11 Oct 2004, 07:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi all,

Suppose you take the case of rolling two die and trying to calculate the probability of getting a total more than 10.

So out of 36 possible outcomes you get :-

A B
5,6
6,5
6,6
6,6*

The last one is what confuses me - most sources don't consider it but I feel the prob should be 4/36 rather than 3/36. If you ignore the possibility of the either of the dice turning up sixes as two separate events aren't you messing with the identity of the dice ?

I may be way off track and I don't mean to shake the very foundations of probability what do you say ?
Manager
Joined: 30 Apr 2004
Posts: 50
Location: NYC
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11 Oct 2004, 09:49
conalcharles wrote:
Hi all,

Suppose you take the case of rolling two die and trying to calculate the probability of getting a total more than 10.

So out of 36 possible outcomes you get :-

A B
5,6
6,5
6,6
6,6*

The last one is what confuses me - most sources don't consider it but I feel the prob should be 4/36 rather than 3/36. If you ignore the possibility of the either of the dice turning up sixes as two separate events aren't you messing with the identity of the dice ?

I may be way off track and I don't mean to shake the very foundations of probability what do you say ?

Are you trying to say that the probability of rolling 6-6 is 2/36??? The probability of the sum being >10 is the probability the sum is 11 + the probability the sum is 12. There are 2 ways the sum can be 11: die A = 6, die B = 5 OR die A = 5, die B = 6. There is only 1 way the sum can be 12: die A = 6, die B = 6. Since there are no differentiating characteristics between the 6s, this is the only way you can roll a 12.
Re: Fundamental probability question....   [#permalink] 11 Oct 2004, 09:49
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