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Geometry

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Intern
Joined: 21 Jan 2013
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Location: India
WE: Engineering (Telecommunications)
Geometry [#permalink]

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13 Jan 2014, 21:13
A polygon has 65 diagonals. What is the number of sides of the same polygonal?

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Manager
Joined: 23 Jun 2008
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Location: Australia
Schools: AGSM '22
GMAT Date: 04-01-2014
Re: Geometry [#permalink]

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13 Jan 2014, 22:36
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formula for diagonals is n(n-3)/2 = #of diagonals

n is the number of sides.

So the answer would be 13 if we plug in the above formula.

005ashok wrote:
A polygon has 65 diagonals. What is the number of sides of the same polygonal?

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Last edited by code19 on 19 Jan 2014, 15:34, edited 1 time in total.

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Re: Geometry [#permalink]

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13 Jan 2014, 23:11
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Expert's post
005ashok wrote:
A polygon has 65 diagonals. What is the number of sides of the same polygonal?

If you are given the number of sides of a polygon, how do you get the number of diagonals?
You say that given n sides, the number of vertices will be n and for every diagonal you need to select two of these n vertices. From this, you need to subtract 'n' because this selection includes the cases in which we select adjacent vertices too (which form the n sides, not diagonals).
No of diagonals = nC2 - n = n(n-1)/2 - n = 65
On solving, you get n = 13 (or you can plug the options)
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Kudos [?]: 17369 [1], given: 232

Re: Geometry   [#permalink] 13 Jan 2014, 23:11
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