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# Geometry Problem HELPPPPPPPPPP urgentttt

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Intern
Joined: 06 Oct 2011
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11 Nov 2011, 20:02
In the figure, AB=5cm, BC=4cm and AC=7 cm. If BX bisects ABC, calculate the length of AX. Please give full explanation. what is why.. how is what
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Manager
Status: Enjoying the MBA journey :)
Joined: 09 Sep 2011
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Location: United States (DC)
Concentration: General Management, Entrepreneurship
GMAT 1: 710 Q49 V38
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Re: Geometry Problem HELPPPPPPPPPP urgentttt [#permalink]

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11 Nov 2011, 23:13
Here's the explanation:

It is given that BX bisects the angle ABC. Therefore, angle ABX = angle CBX
Also, side AB is similar to side CB and since side BX is common to both triangles ABX and CBX, they are similar.

Using property of similarity, we know that AB/AX = BC/CX
Therefore, by alternando (operation on the above fraction),
AB/BC = AX/CX
We know that AB = 5 and BC = 4
Therefore, AX/CX = 5/4
Performing componendo on both sides,
AX+CX/CX = (5+4)/4 = 9/4
But AX+CX = AC = 7 (given)

Therefore, the above equation becomes 7/CX = 9/4
This can be solved to get the value of CX as 28/9 which is equal to 3.11 cm

Now, we are asked to find the length of AX which is AC-CX
Therefore, AX = 7 - 28/9 = 35/9 = 3.89 cm

Hope this helps.

Cheers!
_________________

MBA Candidate 2015 | Georgetown University

Kudos [?]: 136 [0], given: 16

Re: Geometry Problem HELPPPPPPPPPP urgentttt   [#permalink] 11 Nov 2011, 23:13
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