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# Geometry question

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07 Oct 2006, 13:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Do you guys understand this question?

The equation defines a circle in x and y axis. How many integers are over that circle?

The possible answers are: 0, 4, 8, 10, 12

The answer is supposed to be 8 (??????)
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07 Oct 2006, 16:18
whats the equation?
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07 Oct 2006, 19:20
londonluddite wrote:
whats the equation?

It's x^2+y^2=10
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07 Oct 2006, 19:31
kaitibruck wrote:
londonluddite wrote:
whats the equation?

It's x^2+y^2=10

also what you mean how many integers over that cirlce? do you mean inside? on x/y plane?

so x^2+y^2=10, so radius=sqrt(10) and circle center is origin

so I'd imagine -1,-2,-3,0,1,2,3 all fall into the circle, but that's only 7
07 Oct 2006, 19:31
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# Geometry question

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