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Given A + B = 5. Is A > B?

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101mba101
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Given A + B = 5. Is A > B? [#permalink] New post  Updated on: 27 May 2018, 04:31
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Given \(A + B = 5\). Is \(A > B?\)


(1) \(A^2 > B^2\)

(2) \(B < 0\)
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Originally posted by 101mba101 on 27 May 2018, 04:26.
Last edited by Bunuel on 27 May 2018, 04:31, edited 1 time in total.
Renamed the topic and edited the question.
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Bunuel
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Re: Given A + B = 5. Is A > B? [#permalink] New post  27 May 2018, 04:37
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Given \(A + B = 5\). Is \(A > B?\)


(1) \(A^2 > B^2\);

\(A^2 - B^2>0\);

\((A + B)(A - B)>0\);

Since given then A + B = 5, then \(5(A - B)>0\);

\(A - B > 0\);

\(A > B\).

Sufficient.


(2) \(B < 0\).

We know that A + B = 5 = positive and that B is negative. If A also were negative, then the sum of two negative numbers couldn't be positive, therefore A must be positive: (A = positive) > (B = negative). Sufficient.


Answer: D.

Hope it's clear.
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101mba101
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Re: Given A + B = 5. Is A > B? [#permalink] New post  27 May 2018, 04:44
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Thank you so much Bunuel! Super easy explanation.

Bunuel wrote:
Given \(A + B = 5\). Is \(A > B?\)


(1) \(A^2 > B^2\);

\(A^2 - B^2>0\);

\((A + B)(A - B)>0\);

Since given then A + B = 5, then \(5(A - B)>0\);

\(A - B > 0\);

\(A > B\).

Sufficient.


(2) \(B < 0\).

We know that A + B = 5 = positive and that B is negative. If A also were negative, then the sum of two negative numbers couldn't be positive, therefore A must be positive: (A = positive) > (B = negative). Sufficient.


Answer: D.

Hope it's clear.
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Re: Given A + B = 5. Is A > B? [#permalink] New post  27 May 2018, 09:49
Can u plz explain statement 1

Sent from my CPH1727 using GMAT Club Forum mobile app
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Bunuel
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Re: Given A + B = 5. Is A > B? [#permalink] New post  27 May 2018, 09:54
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Anshup wrote:
Can u plz explain statement 1

Sent from my CPH1727 using GMAT Club Forum mobile app


It is explained here: https://gmatclub.com/forum/given-a-b-5- ... l#p2067779
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Re: Given A + B = 5. Is A > B? [#permalink] New post  23 Mar 2023, 10:25
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Re: Given A + B = 5. Is A > B? [#permalink]
23 Mar 2023, 10:25
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