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# Given letters ABCCD how many different ways can a group of

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CEO
Joined: 15 Aug 2003
Posts: 3454

Kudos [?]: 919 [0], given: 781

Given letters ABCCD how many different ways can a group of [#permalink]

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18 Sep 2003, 12:53
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Given letters ABCCD how many different ways can a
group of 3 can be formed with these letters.

Kudos [?]: 919 [0], given: 781

Intern
Joined: 17 Sep 2003
Posts: 21

Kudos [?]: 12 [0], given: 0

Location: GMAT Maze, Chaos.
Re: PS : Counting Methods # 7 ..letters [#permalink]

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18 Sep 2003, 16:16
praetorian123 wrote:
Given letters ABCCD how many different ways can a
group of 3 can be formed with these letters.

Treating the two Cs as 1, we have 4 letters.

The first letter in the group can be chosen in 4 ways, the second letter in 3 ways and the third letter in 2 ways.

So the total number of ways is 4 x 3 x 2 = 24.

Please correct me if I m wrong, my test is on saturday

Kudos [?]: 12 [0], given: 0

CEO
Joined: 15 Aug 2003
Posts: 3454

Kudos [?]: 919 [0], given: 781

Re: PS : Counting Methods # 7 ..letters [#permalink]

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18 Sep 2003, 23:29
vasurajiv wrote:
praetorian123 wrote:
Given letters ABCCD how many different ways can a group of 3 can be formed with these letters.

Treating the two Cs as 1, we have 4 letters.

The first letter in the group can be chosen in 4 ways, the second letter in 3 ways and the third letter in 2 ways.

So the total number of ways is 4 x 3 x 2 = 24.

Please correct me if I m wrong, my test is on saturday

This is not permutations. ABC is the same as CBA

try again

Kudos [?]: 919 [0], given: 781

Intern
Joined: 16 Jul 2003
Posts: 32

Kudos [?]: [0], given: 0

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20 Sep 2003, 00:13
7. There are 4 different letters A, b,c(2times) and d.

3 letters can be selected in 2 different ways -

first, when all 3 are different - 4c3=4
second, when 2 of the 3 selected are same = 2c2*3c1 = 3

Total groups = 7.

Kudos [?]: [0], given: 0

20 Sep 2003, 00:13
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