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Given that n = 10^a + 10^b + 10^c, where a, b, and c are distinct

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Given that n = 10^a + 10^b + 10^c, where a, b, and c are distinct [#permalink]

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Given that \(n = 10^a + 10^b + 10^c\), where a, b, and c are distinct positive integers, how many different positive values of n result if n is less than 1 billion (1,000,000,000) ?

A. 28
B. 36
C. 56
D. 84
E. 120
[Reveal] Spoiler: OA

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Last edited by Bunuel on 28 Nov 2017, 19:33, edited 2 times in total.
Renamed the topic.

Kudos [?]: 1603 [0], given: 282

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Kudos [?]: 6128 [3], given: 121

Given that n = 10^a + 10^b + 10^c, where a, b, and c are distinct [#permalink]

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Gnpth wrote:
Given that \(n = 10^a + 10^b + 10^c\), where a, b, and c are distinct positive integers, how many different positive values of n result if n is less than 1 billion (1,000,000,000) ?

A. 28
B. 36
C. 56
D. 84
E. 120



Hi,

The max value of a, b or c can be 8 to Keep the value \(< 10^9\)..
Any of the three a,b, or c being 9 means \(10^9+..+..>10^9\)

Also a,b,c are distinct, so the answer is nothing but choosing 3 out of 8..
here arrangement is not important, so work on COMBINATION
\(8C3=\frac{8!}{5!3!}=\frac{8*7*6}{3*2}=56\)
C
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

Kudos [?]: 6128 [3], given: 121

Given that n = 10^a + 10^b + 10^c, where a, b, and c are distinct   [#permalink] 28 Nov 2017, 19:31
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Given that n = 10^a + 10^b + 10^c, where a, b, and c are distinct

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