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# Given that x ≠ 0, is [m]\sqrt[3]{x}>\sqrt[5]{x}​​​​[/m]?

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SC Moderator
Joined: 23 Sep 2015
Posts: 1558
Given that x ≠ 0, is [m]\sqrt[3]{x}>\sqrt[5]{x}​​​​[/m]?  [#permalink]

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02 Dec 2018, 01:25
00:00

Difficulty:

(N/A)

Question Stats:

17% (01:54) correct 83% (00:35) wrong based on 12 sessions

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Given that x ≠ 0, is $$\sqrt[3]{x}>\sqrt[5]{x}​​​​$$?

Statement #1: x < 1

Statement #2: x > –1

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Simple strategy:
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Math Expert
Joined: 02 Sep 2009
Posts: 51215
Re: Given that x ≠ 0, is [m]\sqrt[3]{x}>\sqrt[5]{x}​​​​[/m]?  [#permalink]

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02 Dec 2018, 01:29
aragonn wrote:
Given that x ≠ 0, is $$\sqrt[3]{x}>\sqrt[5]{x}​​​​$$?

Statement #1: x < 1

Statement #2: x > –1

Discussed here: https://gmatclub.com/forum/given-that-x ... 73157.html
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Re: Given that x ≠ 0, is [m]\sqrt[3]{x}>\sqrt[5]{x}​​​​[/m]? &nbs [#permalink] 02 Dec 2018, 01:29
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