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# Given two similiar triangles, if the area of one triangle,

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Senior Manager
Joined: 11 May 2004
Posts: 454
Location: New York
Given two similiar triangles, if the area of one triangle, [#permalink]

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10 Nov 2005, 07:45
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Given two similiar triangles, if the area of one triangle, side s, is twice the area of the second triangleside S, then in terms of s, S =

(sqrt2/2)s
(sqrt3/2)s
sqrt2s
sqrt3s
2s

A
Manager
Joined: 04 Oct 2005
Posts: 246

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10 Nov 2005, 08:03
the stem sounds kinda awkward.. could you clarify a little? are the commas where they should be?

I calculated something and came up with ssqrt(1/2)
still not sure because of the stem.
VP
Joined: 30 Sep 2004
Posts: 1480
Location: Germany

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10 Nov 2005, 08:54
area 1 = s^2/2....area 2 = S^2/2....s^2/2 = 2*S^2/2...s * sqrt(1/2) = S...its not given...
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

Director
Joined: 24 Oct 2005
Posts: 572
Location: NYC

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10 Nov 2005, 08:55
can someone tell me why area is s^2/2 ?
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VP
Joined: 30 Sep 2004
Posts: 1480
Location: Germany

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10 Nov 2005, 08:59
bewakoof wrote:
can someone tell me why area is s^2/2 ?

i assumed a triangle with 1:1:sqrt(2)...area of this triangle with side s is s*s*1/2=s^2/2
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

Director
Joined: 24 Oct 2005
Posts: 572
Location: NYC

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10 Nov 2005, 09:05
christoph wrote:
bewakoof wrote:
can someone tell me why area is s^2/2 ?

i assumed a triangle with 1:1:sqrt(2)...area of this triangle with side s is s*s*1/2=s^2/2

i see so you assumed it was a right triangle. what if it is not?? coz it doesnt say..
_________________

Success is my only option, failure is not -- Eminem

VP
Joined: 30 Sep 2004
Posts: 1480
Location: Germany

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10 Nov 2005, 09:13
bewakoof wrote:
christoph wrote:
bewakoof wrote:
can someone tell me why area is s^2/2 ?

i assumed a triangle with 1:1:sqrt(2)...area of this triangle with side s is s*s*1/2=s^2/2

i see so you assumed it was a right triangle. what if it is not?? coz it doesnt say..

it doesn`t matter. its like picking numbers. pick a triangle that fits for the statement to be true.
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

VP
Joined: 22 Aug 2005
Posts: 1112
Location: CA

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10 Nov 2005, 09:43
I guess question is asking to find raio of sides for two similar triangles.

if A and B are similar:
Area(a) / Area(B) = sidea^1/side2^2

putting value:
2/1 = s1^2/s2^2 or s1 = sqrt(s2) * 2
SVP
Joined: 28 May 2005
Posts: 1705
Location: Dhaka

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10 Nov 2005, 10:33
from the question my understanding is that one of the side of one triangle is s and another side of simillar triangle is S

if the triangles are simillar.

then area of triangle 1/ area of triangle 2 = sidea^1/side2^2

or 2/1 = s^2/S^2

so S = s/sqrt2
or you can re write is as (sqrt2/2) * s

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Senior Manager
Joined: 11 May 2004
Posts: 454
Location: New York

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10 Nov 2005, 11:52
Guys,

Sorry for the confusion, the actual question has two diagrams. A small triangle and a large triangle. Both triangles are similiar triangles. the smaller triangle has side 's' and the larger triangle has side 'S'. The are of the smaller triangle can be x, and the area of the larger triangle can be 2x.

I hope that clears any confusion. btw, the OA (as mentioned is C). I got C by picking number, is there some concept I'm missing that would make the question easier?

Thanks!

desiguy wrote:
Given two similiar triangles, if the area of one triangle, side s, is twice the area of the second triangleside S, then in terms of s, S =

(sqrt2/2)s
(sqrt3/2)s
sqrt2s
sqrt3s
2s

A
Intern
Joined: 01 Jun 2005
Posts: 40

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10 Nov 2005, 12:22
desiguy wrote:
Guys,

Sorry for the confusion, the actual question has two diagrams. A small triangle and a large triangle. Both triangles are similiar triangles. the smaller triangle has side 's' and the larger triangle has side 'S'. The are of the smaller triangle can be x, and the area of the larger triangle can be 2x.

I hope that clears any confusion. btw, the OA (as mentioned is C). I got C by picking number, is there some concept I'm missing that would make the question easier?

Thanks!

desiguy wrote:
Given two similiar triangles, if the area of one triangle, side s, is twice the area of the second triangleside S, then in terms of s, S =

(sqrt2/2)s
(sqrt3/2)s
sqrt2s
sqrt3s
2s

A

for similar triangles=> ratio of sides are equal => s/S = h/H

I am just naming the height of each triangle as h and H. since they are similar the heights will be in the same ratio.

2 x Area of small triangle = Area of big triangle

or, 2 x (1/2) s x h = (1/2) S x H
or, s x h = (1/2) S x H
or, S = 2s x h/H
or, S = 2s x s/S
or S^2 = 2 s^2
or S = sqrt(2). s
Re: Geometry - Triangles   [#permalink] 10 Nov 2005, 12:22
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