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Sorry for the confusion, the actual question has two diagrams. A small triangle and a large triangle. Both triangles are similiar triangles. the smaller triangle has side 's' and the larger triangle has side 'S'. The are of the smaller triangle can be x, and the area of the larger triangle can be 2x.

I hope that clears any confusion. btw, the OA (as mentioned is C). I got C by picking number, is there some concept I'm missing that would make the question easier?

Thanks!

desiguy wrote:

Given two similiar triangles, if the area of one triangle, side s, is twice the area of the second triangleside S, then in terms of s, S =

Sorry for the confusion, the actual question has two diagrams. A small triangle and a large triangle. Both triangles are similiar triangles. the smaller triangle has side 's' and the larger triangle has side 'S'. The are of the smaller triangle can be x, and the area of the larger triangle can be 2x.

I hope that clears any confusion. btw, the OA (as mentioned is C). I got C by picking number, is there some concept I'm missing that would make the question easier?

Thanks!

desiguy wrote:

Given two similiar triangles, if the area of one triangle, side s, is twice the area of the second triangleside S, then in terms of s, S =

(sqrt2/2)s (sqrt3/2)s sqrt2s sqrt3s 2s

Pleae show your calcs

A

for similar triangles=> ratio of sides are equal => s/S = h/H

I am just naming the height of each triangle as h and H. since they are similar the heights will be in the same ratio.

2 x Area of small triangle = Area of big triangle

or, 2 x (1/2) s x h = (1/2) S x H
or, s x h = (1/2) S x H
or, S = 2s x h/H
or, S = 2s x s/S
or S^2 = 2 s^2
or S = sqrt(2). s