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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
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Bunuel wrote:
Messi and Ronaldo are playing chess till one of them wins a total of four games. If each of them is equally likely to win any game and no game ends in a draw, what is the probability that at least six games will be played?

(A) 3/8
(B) 7/16
(C) 1/2
(D) 9/16
(E) 5/8


 


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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
I did it without calculation just with observation !!

The max number of games that can be played is 7 (since after 4 wins of any player the game will end)
The min number of games that can be played is 4 (i.e, first four wins of a player)

Since there are equal chances of winning and losing a match, there is 50% probability that atleast 6 games will be played.

IMO Option C
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
Answer: C

The probability of first four games to be played will be 1.
For 5th game to be played, probability will be 1/2 since the game will be either played or not played. This will depend on the result whether anyone has win total four games by previous game.
Similarly, for any game to be played after 5th the probability will be 1/2 as the game will be either played or not played.
It won't matter if at least six games will be played or 90th game will be played.
Therefore, probability that at least six games will be played = 1/2
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
The answer is (D) 9/16
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
Getting answer as C

Just a wild Guess
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
IMO B. The clever guess)
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
Imo D

Probability that at least six games will be played = 1- (Probability of 1 game+ 2 games+ 3 games + 4games +5 games) ---- (1)

Probability that 1 or 2 or 3 game is played is 0 as they both need at least 4 games to win the game.
Probability that 4 games are played is that all are either won by Messi or Ronaldo = (1/ 2^4)+(1/2^4)
Probability that 5 games are played is that 4 won by messi and one loss by Messi and same for Ronaldo = ((5!/4!)/2^5 +(5!/4!)/2^5)

Putting above values in equation (1), we get Probability that at least six games will be played = 9/16
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
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Bunuel wrote:
Messi and Ronaldo are playing chess till one of them wins a total of four games. If each of them is equally likely to win any game and no game ends in a draw, what is the probability that at least six games will be played?

(A) 3/8
(B) 7/16
(C) 1/2
(D) 9/16
(E) 5/8

 


This question was provided by GMAT Club
for the GMAT Club World Cup Competition

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Given information:
1) Messi and Ronaldo are playing chess till one of them wins a total of 4 games.
2) Each likely to win
3) No draw
To determine: Probability(At least 6 games will be played)

Inferences:
1) Total possible options for a single game = 2 (Messi win or Ronaldo win, because no draw)
2) P(Either to win a game) = 1/2
3) P(At least 6 games) = 1 - Probability(Less than 6 games)


So, we need to actually determine P(Less than 6 games) {and subtract the result from 1} and minimum possible number of games for match to finish is 4 so we need to find the P(game finishing in 4 games) or P(game finishing in 5 games)
P(Less than 6 games) = P(4 games) + P(5 games)

P(4 games)

Case 1: Messi winning all
Total possible outcomes = 2*2*2*2 = 16
Favorable outcomes = 1
P = 1/16

Case 2: Ronaldo winning all
Total possible outcomes = 2*2*2*2 = 16
Favorable outcomes = 1
P = 1/16

Total = Messi winning all or Ronaldo winning all = 1/16 + 1/16 = 1/8

P(5 games)

Case 1: Messi winning 4 and Ronaldo winning 1 {RMMMM}
Total possible outcomes = 2*2*2*2*2 = 32
Total favorable outcomes = {5!/4!} - 1 = 4 [The reason for -1 is that there is one combination which will be MMMMR which means Messi wins the first 4 games but game will finish at that point so cannot have 5 games at that point and already covered 4 games scenario in previous part]
P = 4/32 = 1/8

Case 2: Ronaldo winning 4 and Messi winning 1 {MRRRR}
Total possible outcomes = 2*2*2*2*2 = 32
Total favorable outcomes = {5!/4!} - 1 = 4 [The reason for -1 is same as above]
P = 4/32 = 1/8

Total P = 2/8 = 2/8

Now: P(Less than 6) = P(4) + P(5) = 1/8 + 2/8 = 3/8

P(At least 6) = 1 - P(Less than 6) = 1 - (3/8) = 5/8

Answer - E
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
1
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Bunuel wrote:
Messi and Ronaldo are playing chess till one of them wins a total of four games. If each of them is equally likely to win any game and no game ends in a draw, what is the probability that at least six games will be played?

(A) 3/8
(B) 7/16
(C) 1/2
(D) 9/16
(E) 5/8


 


This question was provided by GMAT Club
for the GMAT Club World Cup Competition

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There are two possibilities with OR condition
1. Both the players have equal wins hence Messi wins 3 and Ronaldo wins 3
2. Either Messi or Ronaldo wins at least 2 games from the initial 5 games

Now basis of conditional probability we have
6C3 (1/2)^6 + 5C2 (1/2)^5
=> 20/2^6 + 20/2^6
=> 40/64 = 5/8

IMHO Option E
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
Favourable outcome=WWWLL (order does not matter)
So, 5!/3!2!=10
Since either Messi or Ronaldo may win, we need to multiply by 2 i.e. 10*2=20
Total outcomes=2^5=32
Probability=20/32=5/8
The answer is E.

Originally posted by Kushchokhani on 14 Jul 2022, 07:50.
Last edited by Kushchokhani on 24 Oct 2022, 07:19, edited 1 time in total.
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
P(at least 6 games will be played)= 1-P(less than 6 games are played)

To get the result we need a minimum 4 games to be played
When four games are played, all the games should either be won by Messi or Ronaldo
P (result in 4 games)= 1/2*1/2*1/2*1/2*2= 1/8 (this is the result for either Messi or Ronaldo)

When 5 games are played, the following are the possibilities:
MRRRR, RMRRR, RRMRR, RRRMR
or
RMMMM, MRMMM, MMRMM, MMMRM
so 8 cases
P (result in 5 games)= 1/2*1/2*1/2*1/2*1/2*8= 1/4

P (result in 4 games)+ P(result in 5 games)= 1/8+1/4=3/8

P(atleast 6 games) 1-3/8=5/8
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
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Re: GMAT Club World Cup 2022 (DAY 3): Messi and Ronaldo are playing chess [#permalink]
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