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GMAT Diagnostic Test Question 14 [#permalink]
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06 Jun 2009, 22:24
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GMAT Diagnostic Test Question 14Field: modules Difficulty: 600 If \(1<x<5\) then which of the following must be true? A. \(3x < 3\) B. \(x < 4\) C. \(x2 > 2\) D. \(2 + x > 3\) E. \(x  2 < 3\)
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Last edited by bb on 28 Sep 2013, 21:27, edited 4 times in total.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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01 Jul 2009, 08:04
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Explanation:Official Answer: EA. \(3x < 3\) > absolute value is always nonnegative, hence this options is wrong for any value of \(x\); B. \(x < 4\) > not necessarily true: consider \(x=4.5\); C. \(x  2 > 2\) > \(x>4\) > not necessarily true: consider \(x=3\); D. \(2 + x > 3\) > not necessarily true: consider \(x=0\); So, we are left with option E only. Just to check: E. \(x2 < 3\) > \(3<x2<3\) > add 2 to each part: \(1<x<5\). So, this option is basically the same as the condition given in the stem. Answer: E.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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20 Jul 2009, 21:02
Can someone please explain in more detail why B is wrong? I'm plugging in different values and I can't find one between 1 and 5 that doesn't satisfy the inequality.



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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20 Jul 2009, 21:21
topher wrote: Can someone please explain in more detail why B is wrong? I'm plugging in different values and I can't find one between 1 and 5 that doesn't satisfy the inequality. You should approach it the "opposite" way  instead try values outside of the (1; 5) range and see if they work  for example (4). The question is asking you, which equation below represents the best a condition where 1 < x < 5, not which of the following equations will work with values of x.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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15 Sep 2009, 20:42
The question is
Which of the following inequalities satisfies the condition if the values of x are between 1 and 5?
Clearly states 1 < x < 5 and asking which of below will satisfy and I guess B will satisfy. Else have to refrain q clearly.
thxs



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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17 Sep 2009, 23:06
bb wrote: Which of the following inequalities satisfies the condition if the values of x are between 1 and 5?
A. 3 – x < 3 B. 1< x < 5 C. x  2 > 2 D. 2 + x > 3 E. x – 2 < 3 dzyubam, I tried to send you PM but it did not go for some reasons. The PM is still in my outbox. B and E both satisfiy the conditions given in the question. B. 1 < x < 5 > \(x\) will always be greater than 1, so we are left with \(x < 5\), from where \(x \in (5,5)\). B is out too. * (5, 5) should be (1, 5). * Any value for x satisfies the condition in B. E. x – 2 < 3 > \(x \in (1,5)\). E is the correct answer. * Any value for x satisfies the condition in E. So B and E both are same. I guess the question needs to be modified.. Subject: GMAT Diagnostic Test Question 13dzyubam wrote: Explanation:
Official Answer: EA. 3 – x < 3 > no expression under modulus can be negative. A is out. B. 1 < x < 5 > \(x\) will always be greater than 1, so we are left with \(x < 5\), from where \(x \in ( 5,5)\). B is out too. C. x  2 > 2 > it can be rewritten as \(x > 4\), \(x\) can be any number outside the range (4,4). C is out too. D. 2 + x > 3 > \(x \in (\infty, 5) \cup (1,\infty)\). D is out. E. x – 2 < 3 > \(x \in (1,5)\). E is the correct answer.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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18 Sep 2009, 04:26
Agree with GMATTiger, the question clearly states that x lies between 1 and 5. so we should just ignore the 'other' values i.e. 5<x<=1 for B. B should also satisify the equation.



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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18 Sep 2009, 05:53
well, I'm so new to gmat but both b and e may seem like a correct answer, in the actual test I will still prefer e because b probably should seem a trick to me, the absolute value of any number can't be below zero, so I think it's a false expression from the start, right? or am I mixing things?



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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24 Sep 2009, 00:15
Sorry guys, I had limited access to Internet for 10 days. I agree the question is ambiguous. It has to be reworded somehow. Here are my two suggestions: Which of the following inequalities satisfies the condition that the values of \(x\) are between 1 and 5? Which of the following inequalities has solution for \(x\) in the range \((1,5)\)? What do you all think? Is either of the rewordings any better than the original?
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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25 Sep 2009, 23:39
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dzyubam wrote: Sorry guys, I had limited access to Internet for 10 days. I agree the question is ambiguous. It has to be reworded somehow. Here are my two suggestions:
Which of the following inequalities satisfies the condition that the values of \(x\) are between 1 and 5? Which of the following inequalities has solution for \(x\) in the range \((1,5)\)?
What do you all think? Is either of the rewordings any better than the original? I would go for the following: Quote: Which of the following inequalities must be true if the values of x are between 1 and 5?
A. 3 – x < 3 B. 1< x < 5 C. x  2 > 2 D. 2 + x > 3 E. x – 2 < 3
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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26 Sep 2009, 03:36



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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15 Oct 2009, 14:13
pls explain how x2<3 is x(1,5) ...really need help !



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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15 Oct 2009, 14:28
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In order to solve the modulus inequality you have to consider two possible values of \(x\): a positive one and a negative one. First, you just strip the modulus signs and solve the inequality: \(x2<3\) \(x<5\) This is the range of \(x\) for positive values of \(x\). Now you need to solve a different inequality for negative \(x\): \(x+2<3\) \(x>1\) What we did here is flip the signs of the expression inside the modulus and solve the new inequality. This is range of \(x\) for negative \(x\). Combining both \(x<5\) and \(x>1\) you get the solution \(x \in (1,5)\). harjaskooner wrote: pls explain how x2<3 is x(1,5) ...really need help !
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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16 Oct 2009, 11:15
dzyubam wrote: In order to solve the modulus inequality you have to consider two possible values of \(x\): a positive one and a negative one. First, you just strip the modulus signs and solve the inequality: \(x2<3\) \(x<5\) This is the range of \(x\) for positive values of \(x\). Now you need to solve a different inequality for negative \(x\): \(x+2<3\) \(x>1\) What we did here is flip the signs of the expression inside the modulus and solve the new inequality. This is range of \(x\) for negative \(x\). Combining both \(x<5\) and \(x>1\) you get the solution \(x \in (1,5)\). harjaskooner wrote: pls explain how x2<3 is x(1,5) ...really need help ! thanks ! now i understand it !



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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18 Oct 2009, 09:33
harjaskooner wrote: dzyubam wrote: In order to solve the modulus inequality you have to consider two possible values of \(x\): a positive one and a negative one. First, you just strip the modulus signs and solve the inequality: \(x2<3\) \(x<5\) This is the range of \(x\) for positive values of \(x\). Now you need to solve a different inequality for negative \(x\): \(x+2<3\) \(x>1\) What we did here is flip the signs of the expression inside the modulus and solve the new inequality. This is range of \(x\) for negative \(x\). Combining both \(x<5\) and \(x>1\) you get the solution \(x \in (1,5)\). harjaskooner wrote: pls explain how x2<3 is x(1,5) ...really need help ! thanks ! now i understand it ! Guys, my understanding from the GMAT is that between means a closed set i.e. and based on your question does not include the values 1 nor 5 but rather 0, 1, 2, 3 & 4  of course I am assuming x is an integer. This suggest to me that questions of this sort will not appear in the real test as we seem to have two correct answers to the same question, namely B and D



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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18 Oct 2009, 09:53
LUGO wrote: Guys, my understanding from the GMAT is that between means a closed set i.e. and based on your question does not include the values 1 nor 5 but rather 0, 1, 2, 3 & 4  of course I am assuming x is an integer. This suggest to me that questions of this sort will not appear in the real test as we seem to have two correct answers to the same question, namely B and D The highlighted part is not correct. X could be a fraction or ve as well. 1 < x < 5 means values excluding 1 and 5.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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21 Nov 2009, 02:52
I am still having trouble understanding the stem correctly... when I did the problem, i still got both B and E to be true...



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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23 Nov 2009, 06:20
I agree we have to rephrase the question. What it was intended to mean is something like this: Which of the following inequalities has its solution in the range (1,5)? If you guys have a better suggestion, please share. I will update the question when we agree on rephrasing.
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Re: GMAT Diagnostic Test Question 13 [#permalink]
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28 Nov 2009, 22:35
why dont we change the answer choice b itself??
because in the given range B will always hold true...



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Re: GMAT Diagnostic Test Question 13 [#permalink]
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18 Dec 2009, 01:18
Which of the following inequalities represents the same range as of X between 1 and 5?




Re: GMAT Diagnostic Test Question 13
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