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# GMAT Diagnostic Test Question 26

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Re: GMAT Diagnostic Test Question 27 [#permalink]

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09 Oct 2010, 07:54
defoue wrote:
Target760 wrote:
here is my solution:

let's say no of eggs purchased = E

price per dozen of eggs in first case = ($12/E)*12 i.e. price per egg multiply by 12, to get price per dozen new price per dozen = ($12/[E+2])*12

now, the equation is; (old price per dozen) - (new price per dozen) = 1

i.e. {($12/E)*12} - {($12/[E+2])*12} = 1

solve for E, 144/E - 144/(E+2) = 1

144E + 288 - 144E = E(E+2)

288=E^2 +2E

E^2 + 2E - 288 = 0

By factoring we get
E^2 + 18E - 16E -288 = 0
E(E+18)-16(E+18)=0
(E+18)(E-16)=0
E= - 18, or 16

rejecting negative value we get E=16 (the original no of eggs purchased)

no. of eggs brought home = E+2 or 16 + 2 = 18

Hey man, could you pls explain how did you come to your factorization. I do not get the way you're going from :
E^2 + 2E - 288 = 0
to
E(E+18)-16(E+18)=0

Thx very much

You can alway solve through discriminant, but it takes you to 4 + 288*4 = 289*4 =1156 - which makes a bit problem if you dont know the square root of 1156.

My approach:

- as we have -288 one root of the equation must be negative and one positive
- as we have 2E, the yE and xE must sum in 2E ( y+x = 2 - the positive must be greater by 2 in absolute value)

now: 288 is pretty close to 289 which is 17^2.
Try 17+1 and 17-1 which makes 16*18 -> now 16 must be negative.
then:
(x-16)*(x+18) = 0
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Re: GMAT Diagnostic Test Question 27 [#permalink]

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02 Nov 2010, 21:10
I used the same approach..and got my answer.This is a little tricky and took me just about 2 mins..the point is you need to be a little quick on quadratic equations in the calculation part.Nevertheless a good one.

let's say no of eggs purchased = E

price per dozen of eggs in first case = ($12/E)*12 i.e. price per egg multiply by 12, to get price per dozen new price per dozen = ($12/[E+2])*12

now, the equation is; (old price per dozen) - (new price per dozen) = 1

i.e. {($12/E)*12} - {($12/[E+2])*12} = 1

solve for E, 144/E - 144/(E+2) = 1

144E + 288 - 144E = E(E+2)

288=E^2 +2E

E^2 + 2E - 288 = 0

By factoring we get
E^2 + 18E - 16E -288 = 0
E(E+18)-16(E+18)=0
(E+18)(E-16)=0
E= - 18, or 16

rejecting negative value we get E=16 (the original no of eggs purchased)

no. of eggs brought home = E+2 or 16 + 2 = 18

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Re: GMAT Diagnostic Test Question 27 [#permalink]

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05 Jan 2011, 09:38
The way I did it:
Let the total number of eggs bought originally be x,

setting up the eqn 12*(12/x - 12/(x+2))=1 ............... I

Now during the test I used the brute force method where I solved the eqn and then tried to use the quadratic formula to calculate roots of the eqn given above which solves down to i.e x^2+2x-288=0 where I got stuck trying to find the square root of 1156 (its 34 btw). In retrospect I would set up the eqn and start plugging in values to solve it.

when you plug D it satisfies the eqn which boils down to 12*(3/4-2/3) = 1 = RHS of I

The only trick in this is that it gives the value of x which is the total number of eggs before the cook bargained his way to getting more. The answer that the question is looking for is really x+2=18 since it says how many did the cook go home with? (hands up if you missed that part!) hence E
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A question from diagnostic test [#permalink]

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06 Feb 2011, 18:56
A cook went to a market to buy some eggs and paid $12. But since the eggs were quite small, he talked the seller into adding two more eggs, free of charge. As the two eggs were added, the price per dozen went down by a dollar. How many eggs did the cook bring home from the market? Answer is 18, but I did not get the explanation. Manager Joined: 20 Dec 2010 Posts: 168 Location: Stockholm, Sweden Followers: 2 Kudos [?]: 56 [0], given: 5 Re: A question from diagnostic test [#permalink] ### Show Tags 07 Feb 2011, 03:48 Yeah, this one is a bit tricky. Our equation we want will look like Price per dozen before - Price per dozen after (we got the two eggs) = 1 (the difference was 1$)

How do we find the price per dozen?

One way is taking the unit price and multiply by 12

(total price/no of eggs) * 12 = price per dozen

let x denote no of eggs and total price was 12$(12/x)*12 = dozen price before we got the two eggs for free (12/x+2)*12 = dozen price after we got the two eggs for free, and the difference should be 1 so. (12/x)*12 - (12/x+2)*12 = 1 12/x -12/(x+2) =1/12 12(x+2)-12(x) = ((x)(x+2))/12 12x+24-12x = (x^2 +2x)/12 x^2 +2x -288 = 0 x(x+2) - 288 = 0 288 is approximately ~17^2 so we need something near that 18(20) = 360 too much 16(18) = 288 so x is 16 and we will bring home x+2 eggs = 18 _________________ 12/2010 GMATPrep 1 620 (Q34/V41) 01/2011 GMATPrep 2 640 (Q42/V36) 01/2011 GMATPrep 3 700 (Q47/V39) 02/2011 GMATPrep 4 710 (Q48/V39) 02/2011 MGMAT CAT 1 650 (Q46/V32) 02/2011 MGMAT CAT 2 680 (Q46/V36) 02/2011 MGMAT CAT 3 710 (Q45/V41) Math Forum Moderator Joined: 20 Dec 2010 Posts: 2013 Followers: 163 Kudos [?]: 1822 [0], given: 376 Re: A cook [#permalink] ### Show Tags 07 Feb 2011, 05:43 Let x be the number of eggs initially bought. x eggs $$\rightarrow$$$12
1 egg $$\rightarrow$$ (12/x)
12 eggs $$\rightarrow$$ (12*12)/x = 144/x

(x+2)eggs $$\rightarrow$$ $12 1 egg $$\rightarrow$$ 12/(x+2) 12 eggs $$\rightarrow$$ 12*12/(x+2) = 144/(x+2) $$\frac{144}{(x+2)}+1=\frac{144}{x}$$ $$x^2+2x-288=0$$ $$(x-16)(x+18)=0$$ x=16 and x=-18 Count can't be minus; Eggs initially purchased = 16. After adding 2 = 16+2=18 Ans: "E" _________________ SVP Joined: 16 Nov 2010 Posts: 1666 Location: United States (IN) Concentration: Strategy, Technology Followers: 34 Kudos [?]: 533 [0], given: 36 Re: A cook [#permalink] ### Show Tags 07 Feb 2011, 06:05 Hi I have a doubt in this with my approach. Let us assume price per dozen of eggs is x, and he bought total y eggs. So he bought y/12 dozens of eggs. Now we can have 2 equations : y/12 * x = 12 and (y+2)/12 * (x-1) = 12 But this does not give y = 18 , could someone please help me ? Regards, Subhash _________________ Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant) GMAT Club Premium Membership - big benefits and savings Math Forum Moderator Joined: 20 Dec 2010 Posts: 2013 Followers: 163 Kudos [?]: 1822 [0], given: 376 Re: A cook [#permalink] ### Show Tags 07 Feb 2011, 06:21 subhashghosh wrote: Hi I have a doubt in this with my approach. Let us assume price per dozen of eggs is x, and he bought total y eggs. So he bought y/12 dozens of eggs. Now we can have 2 equations : y/12 * x = 12 and (y+2)/12 * (x-1) = 12 But this does not give y = 18 , could someone please help me ? Regards, Subhash Your interpretation is correct. and y will not be equal to 18. It will be 16. y/12 * x = 12 x = 144/y (y+2)/12 * ((144/y)-1)=12 This gets transformed into same equation; $$y^2+2y-288=0$$ Solve for roots; y=16 or y=-18 y can't be negative. y=16. y- number of eggs initially purchases = 16 After adding 2 eggs to this 16+2=18. _________________ Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7372 Location: Pune, India Followers: 2287 Kudos [?]: 15098 [0], given: 224 Re: A question from diagnostic test [#permalink] ### Show Tags 07 Feb 2011, 20:51 sara933 wrote: A cook went to a market to buy some eggs and paid$12. But since the eggs were quite small, he talked the seller into adding two more eggs, free of charge. As the two eggs were added, the price per dozen went down by a dollar. How many eggs did the cook bring home from the market?

Answer is 18, but I did not get the explanation.

Another approach:

Let us say the price per dozen is p.
Since he paid a total of $12, he must have bought 12/p dozens. Total number of eggs = $$(\frac{12}{p})*12$$(because a dozen has 12 eggs) But, he got 2 extra eggs so now total number of eggs = $$(\frac{12}{p})*12 + 2$$ The price per dozen went down by$1 so new price per dozen = (p - 1)
New total number of eggs = $$\frac{12}{(p-1)} * 12$$
$$(\frac{12}{p})*12 + 2 = \frac{12}{(p-1)} * 12$$

We see that we have numerator 144 and denominator p on one side and (p-1) on the other side. Since these are number of eggs, they must be integral values. $$144 = 2^4*3^2$$
We need two consecutive integers both of which divide 144. You can see that 8 and 9 both divide 144. Let's confirm:
$$(\frac{12}{9})*12 + 2 = \frac{12}{8} * 12 = 18$$
So the cook brought 18 eggs home.
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Director Joined: 01 Feb 2011 Posts: 755 Followers: 14 Kudos [?]: 124 [0], given: 42 Re: GMAT Diagnostic Test Question 27 [#permalink] ### Show Tags 17 Apr 2011, 19:53 price per dozen difference is 1 144/x - 144(x+2) = 1 solving we get x = 16 => x+2 = 18 Answer is E. Manager Joined: 10 Jul 2010 Posts: 195 Followers: 1 Kudos [?]: 20 [0], given: 12 Re: GMAT Diagnostic Test Question 27 [#permalink] ### Show Tags 18 Apr 2011, 00:11 im having trouble understanding how multiplying $$\frac{1}{12}$$ reduces the price per dozen by a dollar? Manager Joined: 19 Apr 2011 Posts: 110 Followers: 2 Kudos [?]: 3 [0], given: 2 Re: A cook [#permalink] ### Show Tags 15 Jun 2011, 04:55 I stopped at 16 without adding 2 more eggs. Now i know my mistake. Good Question VP Status: There is always something new !! Affiliations: PMI,QAI Global,eXampleCG Joined: 08 May 2009 Posts: 1335 Followers: 17 Kudos [?]: 254 [0], given: 10 Re: A cook [#permalink] ### Show Tags 16 Jun 2011, 00:36 n/12 = no of dozens thus 12/(n/12) - 12/[(n+2)/12] = 1 144/n - 144/n+2 = > n = 16 thus 18 _________________ Visit -- http://www.sustainable-sphere.com/ Promote Green Business,Sustainable Living and Green Earth !! Intern Joined: 07 Jun 2011 Posts: 23 Followers: 0 Kudos [?]: 0 [0], given: 1 Re: GMAT Diagnostic Test Question 27 [#permalink] ### Show Tags 04 Sep 2011, 06:28 As long as we understand that the cook gets the 2 additional eggs at the same price of 12, we can setup an equation N- Number of eggs P - Price per dozen 12 eggs cost$P
N eggs cost NP/12 and this = 12 --- 1st equation

Now
12 eggs cost $P-1 N+2 eggs cost (N+2)(P-1)/12 and this = 12 ---2nd equation. Here,we know that the cook got the 2 eggs for the same amount of$12

Combining both equations, we have
NP=(N+2)(P-1)
NP = 144

Finally, we get N^2+2N-288=0. Solving this equation, we get N=16. Therefore, the number the cook took back home is 18
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Re: GMAT Diagnostic Test Question 27 [#permalink]

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25 Oct 2011, 16:54
urchin wrote:
my approach.....
Let him buy m number of eggs....
new price per dozen = ($12/[E+2])*12 now, the equation is; (old price per dozen) - (new price per dozen) = 1 i.e. {($12/E)*12} - {($12/[E+2])*12} = 1 solve for E, 144/E - 144/(E+2) = 1 144E + 288 - 144E = E(E+2) 288=E^2 +2E E^2 + 2E - 288 = 0 By factoring we get E^2 + 18E - 16E -288 = 0 E(E+18)-16(E+18)=0 (E+18)(E-16)=0 E= - 18, or 16 rejecting negative value we get E=16 (the original no of eggs purchased) no. of eggs brought home = E+2 or 16 + 2 = 18 Therefore, answer is E Actually, I used the same approach, but did not dare to do the factorization on the timed question, so I used the quadratics formula. E^2 + 2E - 288 = 0 E = {-2 +/- sqrt[4 - 4*(-288)]}/2 => {-2 +/- sqrt[1156]}/2 => {-2 +/- 34}/2 => E =16 => E+2 = 18 Of course, I wasted precious time finding the square root of 1156. I find both methods (quadratics vs factorization) equally cumbersome for this equation. You spent some extra time getting to 1156 and then sqrting it. Would have been more efficient to do 4+4(288) in the radical, which leads to 4(1+288) = (2^2)(17^2). Much quicker. Math Expert Joined: 02 Sep 2009 Posts: 38856 Followers: 7726 Kudos [?]: 106032 [1] , given: 11602 Re: GMAT Diagnostic Test Question 27 [#permalink] ### Show Tags 15 Aug 2013, 02:59 1 This post received KUDOS Expert's post SOLUTION: A cook went to a market to buy some eggs and paid$12. But since the eggs were quite small, he talked the seller into adding two more eggs, free of charge. As the two eggs were added, the price per dozen went down by a dollar. How many eggs did the cook bring home from the market?

A. 8
B. 12
C. 15
D. 16
E. 18

Say the # of eggs the cook originally got was $$x$$;
The price per egg then would be $$\frac{12}{x}$$ and the price per dozen would be $$12*\frac{12}{x}$$.

Now, since the cook talked the seller into adding two more eggs then he finally got $$x+2$$ eggs (notice that $$x+2$$ is exactly what we should find);
So, the price per egg became $$\frac{12}{x+2}$$ and the price per dozen became $$12*\frac{12}{x+2}$$.

As after this the price per dozen went down by a dollar then $$12*\frac{12}{x}-12*\frac{12}{x+2}=1$$ --> $$\frac{144}{x}-\frac{144}{x+2}=1$$. At this point it's better to substitute the values from answer choices rather than to solve for $$x$$. Answer choices E fits: if $$x+2=18$$ then $$\frac{144}{16}-\frac{144}{18}=9-8=1$$.

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Re: GMAT Diagnostic Test Question 27 [#permalink]

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17 Sep 2013, 00:16
prateekbhatt wrote:
dzyubam wrote:
Explanation:
 Rating:

This is a hard equation to come up with during the test. The price of eggs was \$12. Let $$E$$ denote the number of eggs and $$P$$ denote the price.

$$(E+2)\times(P-\frac{1}{12})=12$$

From this equation we get that $$E = 16$$.

Answer: $$E+2=16+2=18$$.

This equation is much more easier than the rest. But definately a 750 level ques.

Honestly, I do not understand $$(P-\frac{1}{12})$$...

Secondly, how do you solve from $$(E+2)\times(P-\frac{1}{12})=12$$ -->$$E = 16$$ - with this "shortcut" it is pretty much useless. Please explain to me how it could be solved, with two variables...Thanks.
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Re: GMAT Diagnostic Test Question 27   [#permalink] 17 Sep 2013, 00:16

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# GMAT Diagnostic Test Question 26

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