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A certain store sells all maps at one price and all books at another price. On Monday the store sold 12 maps and 10 books for a total of $38.00 and on Tuesday the store sold 20 maps and 15 books for a total of $60.00. At this store, how much less does a map sell for than a book?

Re: GMAT paper test...looking for answer [#permalink]

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24 Feb 2010, 12:36

l02g060 wrote:

A certain store sells all maps at one price and all books at another price. On Monday the store sold 12 maps and 10 books for a total of $38.00 and on Tuesday the store sold 20 maps and 15 books for a total of $60.00. At this store, how much less does a map sell for than a book?

a. $.25 b. $.50 c. $.75 d. $1.00 e. $1.25

I am brain dead on how to solve this. Thanks!

Lets assume the price of a map = x and price of the book = y

Re: GMAT paper test...looking for answer [#permalink]

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24 Feb 2010, 23:07

l02g060 wrote:

A certain store sells all maps at one price and all books at another price. On Monday the store sold 12 maps and 10 books for a total of $38.00 and on Tuesday the store sold 20 maps and 15 books for a total of $60.00. At this store, how much less does a map sell for than a book?

a. $.25 b. $.50 c. $.75 d. $1.00 e. $1.25

I am brain dead on how to solve this. Thanks!

Map at rate x books at rate y 12x+10y = 38 20x+15y = 60

Re: GMAT paper test...looking for answer [#permalink]

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26 Feb 2010, 21:08

l02g060 wrote:

chix475ntu wrote:

12m + 10b = 38 (m and b are price of one map and one book respectively) 20m + 15b = 60 b-m?

solving we get m = $1.5, b = $2 and b-m = 0.5

B

Do you prefer solving by addition as in prior answer or by substitution? Which works better on more diffuicult question sets?

I usually solve the problem then look at the solution. And also will try to substitute the answer in the equations(more likely for inequalities). If there are only few variables to work with, its will be much faster to solve than to substitute the answers. And for the difficult problems, you need to work on writing the given sentences into equations(once you can do that in a minute, you are good to go ) - rest would be easy to solve.

12m + 10b = 38 (m and b are price of one map and one book respectively) 20m + 15b = 60 b-m?

solving we get m = $1.5, b = $2 and b-m = 0.5

B

Do you prefer solving by addition as in prior answer or by substitution? Which works better on more diffuicult question sets?

More often than not, solving the equations simultaneously will give you the answer quickly. Solving by substitution is generally more painful with two equations in two variables.

Bring down your equations to lowest form:

1) 6m+5b=19 2) 4m+3b=12

Now, one way is to multiply the first equation by 3 and the second one by 5. But we see that the calculations involved are a little painful. It can be helpful if you are a little more resourceful with your numbers.

Say, I multiply the second equation by 1.5. I get: 6m + 4.5b = 18

Now solve them simultaneously: 6m+5b=19 6m + 4.5b = 18

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