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GMAT Prep : 2 questions Q1

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GMAT Prep : 2 questions Q1 [#permalink]

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New post 26 Jul 2009, 11:45
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D
E

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Last edited by nookway on 26 Jul 2009, 15:20, edited 1 time in total.
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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 26 Jul 2009, 12:18
let x be the max number of student:
5/x > 3/80
hence, 400-3x > 0 ==> x < 400/3 = 133,33.
max number of student = 133.

Answer D

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 08:19
If possible, please post each question in an individual topic.

Question 1 is D.

First try to divide all districts evenly:
132,000/11 = 12,000

In order to lower the population of any single district, we need to raise the population of other districts. For every number that you raise the other districts, you may lower the 11th district tenfold. So if you raise the 10 districts by 100 each from 12,000 to 12,100, you can lower the 11th from 12,000 to 11,000.

Now check to see if you are within 10%:
11,000
x 1.10
12,100
The maximum difference is 10%, so you can't go lower than 11,000.

You want all the 10 districts to be the same population in order to push the 11th district population down as far as possible without breaking the 10% rule.

I know this involves a bit of trial and error, but this is the best I can do...

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 12:46
11000 and 133.

for the first one, the equation to solve for it is 12000+x = 1.1* ( 12000 - 10x), x = 100, 10x = 1000, district that can have the lowest number of resident is 12000 - 1000 = 11000.

for the 2nd one, 80 * 5 / 3 ~= 133.33333 = 133

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 13:03
i think the answer for the first one is B, 10,800

what is the OA

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 13:17
ALD wrote:
i think the answer for the first one is B, 10,800

what is the OA


i dont think 10800 is the answer....

if the least is 10800, then the max the other 10 divisions can be is 11880, the total population would be 118800+10800 = 129600, which is less than the 132000 population of the county

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 13:55
I have a much simpler method:

x + (1.1x)10 = 132,000

Solve for x = 11,000

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 20:45
Q1.

Lets look at it this way........we arrange 11 district in ascending order....x1,x2,x3,x4,....x11 Now any one district could have not more than 10% of other district....since x1 is with lowest population it cannot be compared to anyother state...but x2 =(1.1) x1....similarly.....x3=(1.1)x1......thus total population = x1+ 10(1.1)x1 = 132000 => hence x1 = 11000...OA D
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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 20:48
Q2.
Given that 3/80 < 5/x .......x< 5/3 * 80 ... x < 133.333 ....X = 133...OA D
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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 05 Aug 2009, 21:06
Curious as to what level quant these questions represent... would you say ~Q50?

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Re: GMAT Prep : 2 questions Q1 [#permalink]

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New post 06 Aug 2009, 04:05
OA is D for both.

Thanks guys!

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Re: GMAT Prep : 2 questions Q1   [#permalink] 06 Aug 2009, 04:05
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