Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 29 May 2017, 11:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# GMAT prep II - probability question

Author Message
Intern
Joined: 06 Oct 2007
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 0

GMAT prep II - probability question [#permalink]

### Show Tags

26 Nov 2007, 14:40
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi!
This is a pretty basic one, but I got it wrong...

Josh and Jose work at an auto repair center with 4 other workers. For a survey on health insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that both Josh and Jose will be chosen?

a) 1/15
b) 1/12
c) 1/9
d) 1/6
e) 1/3

Thanks!
-Jackie
CEO
Joined: 17 Nov 2007
Posts: 3585
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 576

Kudos [?]: 3989 [0], given: 360

### Show Tags

26 Nov 2007, 14:56
A

P=1/c(2,6)=4!*2!/6!=2/30=1/15

another way:

P=1/6*1/5+1/6*1/5=1/15
CEO
Joined: 29 Mar 2007
Posts: 2562
Followers: 21

Kudos [?]: 453 [0], given: 0

Re: GMAT prep II - probability question [#permalink]

### Show Tags

26 Nov 2007, 17:34
jthong wrote:
Hi!
This is a pretty basic one, but I got it wrong...

Josh and Jose work at an auto repair center with 4 other workers. For a survey on health insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that both Josh and Jose will be chosen?

a) 1/15
b) 1/12
c) 1/9
d) 1/6
e) 1/3

Thanks!
-Jackie

Oops messed it up a bit.

A.

6!/4! = 30. We have J and J and then J and J. so 2/30= 1/15.
SVP
Joined: 28 Dec 2005
Posts: 1561
Followers: 3

Kudos [?]: 160 [0], given: 2

### Show Tags

16 Dec 2007, 16:44
why do we have to consider two cases, and not just have the probability as 1/6*1/5 ?
CEO
Joined: 17 Nov 2007
Posts: 3585
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 576

Kudos [?]: 3989 [0], given: 360

### Show Tags

17 Dec 2007, 00:00
pmenon wrote:
why do we have to consider two cases, and not just have the probability as 1/6*1/5 ?

we have two cases: (Josh,Jose) and (Jose,Josh)

for (Josh,Jose): 1/6*1/5 and for (Jose,Josh): 1/6*1/5
Manager
Joined: 03 Sep 2006
Posts: 233
Followers: 1

Kudos [?]: 23 [0], given: 0

### Show Tags

17 Dec 2007, 00:28
Late, but A:
2C2 / 6C2
17 Dec 2007, 00:28
Display posts from previous: Sort by