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# GMAT Prep PS - Geometry

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GMAT Prep PS - Geometry [#permalink]

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11 Jun 2006, 19:09
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Hi,

I dont want to waste anymore time trying to figure out the answer for this. If someone can figure this pl. let me know.

See attached
Thank you.
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PS Geometry Question.doc [60.5 KiB]

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11 Jun 2006, 19:22
Just a clarification. THe marked answer (c) is NOT the correct answer. OA to follow.
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Re: GMAT Prep PS - Geometry [#permalink]

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11 Jun 2006, 19:27
hdakshina wrote:
Hi,

I dont want to waste anymore time trying to figure out the answer for this. If someone can figure this pl. let me know.

See attached
Thank you.

Angle of minor arc OP = 2 x inscribed angle ORP
= 2 x 35 = 70deg
Similarly, arc QR = 70deg
Therefore, Arc PQ = 180 -70 -70 = 40deg
length of minor arc PQ = n/360 x circumference
= 40/360 x (pi)(18)
= 2pi
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11 Jun 2006, 19:53
is there another way to approach the problem ?
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11 Jun 2006, 22:33
Denote center of circle as C.

CR = CP = Radius of circle. So CRP = isoceles triangle with angle CPR = angle CRP = 35.

So angle PCR = 110, and angle PCO = 70.

Lenght of arc OP = Length of arc QR = 70/360 * 18pi = 7pi/2

Length of arc PQ
= Length of arc OR (semi-circle) - 2(length of arc OP)
= 9pi - 7pi
= 2pi
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12 Jun 2006, 18:22
Yipe 2*pi is right. OA is (A).
12 Jun 2006, 18:22
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# GMAT Prep PS - Geometry

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