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# GMAT Prep Q9

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Intern
Joined: 21 May 2006
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19 Jul 2006, 14:20
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi,

Can someone help with this question ?

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VP
Joined: 02 Jun 2006
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19 Jul 2006, 15:47
Let item prices be :

b = most expensive
a = second most expensive
c = least expensive

Total of discounts = 0.2b + 0.1a + 0.1c

Is 0.1a+0.2b+0.1c > 0.15(a+b+c)
simplifying b > (a+c)

S1: b = 50, a = 20
As a > c, max value of c < 20, therefore sufficient.

S2: c = 15
As we don't know anything about a or b, not sufficient.

SVP
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20 Jul 2006, 03:08
A.

1)Let the least expensive item be \$1

Discount from most expensive = 20/100 * 50 = 10
Discount from second most = 10/100 *20 = 2
Total discount = 12 + discount from least expensive.

15% discount on the sum of the 3 items = 15/100 * 71 = 10.65

Hence even if we take any miniscule value of the least expensive item. the discount from individual will always be greater than the combined discount.

2) Least expensive item is 15
Let the other two items be 16 and 17 .

The total discount can be less than or greater than the individual discounts .Hence Not suff
Manager
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20 Jul 2006, 21:44
May be I am wrong but I have one question.

Why are we believing that the lowest 2 items are of different prices and not same. From the question I don't seem to find any clue.

Guys please explain if someone know how to identify this.
SVP
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20 Jul 2006, 22:29
No you are right the lowest two items can have the same value.
But still the answer will remain the same...
Calculate if you want.
20 Jul 2006, 22:29
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