It is currently 20 Oct 2017, 13:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# GMATPrep: Algebra. Take a shot!

Author Message
Director
Joined: 01 May 2007
Posts: 795

Kudos [?]: 379 [0], given: 0

GMATPrep: Algebra. Take a shot! [#permalink]

### Show Tags

29 Dec 2007, 11:26
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Kudos [?]: 379 [0], given: 0

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4586 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

### Show Tags

29 Dec 2007, 11:40
E

√x²/x can change sign for positive and negative x. So, |x|/x

Kudos [?]: 4586 [0], given: 360

Senior Manager
Joined: 01 Sep 2006
Posts: 301

Kudos [?]: 28 [0], given: 0

Location: Phoenix, AZ, USA

### Show Tags

29 Dec 2007, 11:41
root x^2 == +/-X o |X|

Kudos [?]: 28 [0], given: 0

Director
Joined: 01 May 2007
Posts: 795

Kudos [?]: 379 [0], given: 0

### Show Tags

29 Dec 2007, 11:45
Correct answer, but I'm not understanding. I understand that the sqroot of x^2 will give me a positive or negative x. But I don't see how that translates into absolute value of x. Can you elaborate?

I said it was 1. I squared the entire thing. got rid of the sqroot on the top. so I had x^2/x^2. Which equals 1.

Kudos [?]: 379 [0], given: 0

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4586 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

### Show Tags

29 Dec 2007, 12:11
|x|=√x² for any x. it is definition.

so, √x²/x=|x|/x always

|x|/x=1 for positive x.
|x|/x=-1 for negative x.

Kudos [?]: 4586 [0], given: 360

Intern
Joined: 13 Nov 2007
Posts: 19

Kudos [?]: 4 [0], given: 0

### Show Tags

29 Dec 2007, 13:36
The value in the numerator is independent of the sign since it is sq(X) and X!=0. Hence |x|

And the denomination can be either positive or negative. Hence just X.

Kudos [?]: 4 [0], given: 0

SVP
Joined: 28 Dec 2005
Posts: 1545

Kudos [?]: 179 [0], given: 2

### Show Tags

29 Dec 2007, 16:10
well, we know that square root always gives a negative and positive value, so the answer to this question cannot be -1 or +1 by itself.

the only logical answer is E, as the absolute value sign takes care of both situations

Kudos [?]: 179 [0], given: 2

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4586 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

### Show Tags

29 Dec 2007, 21:18
pmenon wrote:
well, we know that square root always gives a negative and positive value...

√x² is always positive.
x gives us a negative and positive value

Kudos [?]: 4586 [0], given: 360

29 Dec 2007, 21:18
Display posts from previous: Sort by