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# GMATPrep - DS - Car dealership

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Senior Manager
Joined: 14 Jul 2005
Posts: 402
GMATPrep - DS - Car dealership [#permalink]

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29 Jul 2006, 16:54
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Senior Manager
Joined: 22 May 2006
Posts: 368
Location: Rancho Palos Verdes

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29 Jul 2006, 23:04
S1. 500 cars were expected.
500x were expected to be donated. insufficient
S2. (expected+60)x = 28000 insufficient
Combine S1 and S2
560x = 28000
x = 50
50*500 = 25,000 sufficient

Thus, C.
_________________

The only thing that matters is what you believe.

Last edited by freetheking on 29 Jul 2006, 23:11, edited 2 times in total.
SVP
Joined: 30 Mar 2006
Posts: 1728

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01 Aug 2006, 00:23
C

Let the number of car expected to be sold be C
Then expected donation = Cx

1) Donation = 500x
Not suff

2) (C+60)x = 28000
Cx + 60X = 28000
Not suff

together

C+60 = 500
Hence 500x = 28000
x = 56
Expected donation = 440*56
Senior Manager
Joined: 21 Jun 2006
Posts: 282

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05 Aug 2006, 21:01
C
Statement A is insufficient as there is no information about donation/car
Statement B is also insufficient as we don't know what the expected # of cars were.
A and B together establish that 560 cars raised \$28,000.
05 Aug 2006, 21:01
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