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# GmatPrep - Inequality

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Senior Manager
Joined: 22 Nov 2005
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18 Jun 2006, 07:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Last edited by gmat_crack on 07 Jul 2008, 20:54, edited 1 time in total.

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VP
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18 Jun 2006, 09:08
Should be B. since y>=0, -y cannot be >lx-3l, which is always +ve or 0. ..

therefore, x = 0.

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Director
Joined: 26 Sep 2005
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18 Jun 2006, 19:25
I dont quite uniderstand,

in stmt 2, if Ix-3I<= -Y if you take x=0 then Ix-3I =3 which CANT be lesser than -Y because Y has to be >=0 and has a negative sign.

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GMAT Club Legend
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18 Jun 2006, 19:39
Strange, we're told y is positive, so -y must be negative. |x-3| is a modula operation, which always gives a positive result. How can a positive be less than or equals to a negative? (Statement 2)

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VP
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18 Jun 2006, 20:21
I also agree wity Murti's solution, except for the conclusion.
Given y >= 0
From #2. -y >= |x-3|
|x-3| -- Absolute value -- is always +ve or 0
-y >=0 & y >=0 can only be possible if y = 0.
Hence |x-3| = 0 or x = 3 SUFF.

From #1 y <=|x-3| x & y can take any value as long as 0=<y<|x-3|
INSUFF to find x.
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"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

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VP
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18 Jun 2006, 21:24
MA wrote:
Should be B. since y>=0, -y cannot be >lx-3l, which is always +ve or 0. ..

therefore, x = 0.

x = 3. that was a typo.

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Manager
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19 Jun 2006, 00:39
Ans is B.

Since y >= 0, |x-3| <= -y. The value has to be 0. So x = 3.

In A there are a myriad possibilities.
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Thanks,
Zooroopa

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19 Jun 2006, 00:39
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# GmatPrep - Inequality

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