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GMATPrep: Probability Radio stations.

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Senior Manager
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GMATPrep: Probability Radio stations. [#permalink]

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New post 02 Jul 2006, 07:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please explaine your answer, thank you.
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New post 02 Jul 2006, 08:15
d) 0.657 ?

the probability that A plays song that Leo does't like = 7/10
the probability that B plays song that Leo does't like = 7/10
the probability that C plays song that Leo does't like = 7/10


0.7^3 = 0.343

1-0.343 = 0.657
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New post 02 Jul 2006, 09:57
Agree it should be D.

P(Listening to a song) = 1 - P(Not listening to song on A or B or C) = 1- {7/10*7/10*7/10} = 657/1000
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New post 02 Jul 2006, 11:17
Yep. Looks like D. as per explanations abov.
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New post 03 Jul 2006, 23:06
Yes guys OA is D 0.657.

Thank you for explanations.

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New post 03 Jul 2006, 23:21
another approach

Probability that A plays the right music = 0.3
Probability that B plays the right music = 0.7*0.3 = .21
Probabiltiy that C plays the right music = 0.7*0.7*0.3 = .147

Total = 0.657

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New post 04 Jul 2006, 00:15
jaynayak wrote:
another approach

Probability that A plays the right music = 0.3
Probability that B plays the right music = 0.7*0.3 = .21
Probabiltiy that C plays the right music = 0.7*0.7*0.3 = .147

Total = 0.657


This is exaxtly the approach I used.
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  [#permalink] 04 Jul 2006, 00:15
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