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# Half of the company's employees work in manufacturing. 20%

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Current Student
Joined: 11 May 2008
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Half of the company's employees work in manufacturing. 20% [#permalink]

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30 Aug 2008, 03:59
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Difficulty:

(N/A)

Question Stats:

50% (01:55) correct 50% (03:21) wrong based on 19 sessions

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Half of the company's employees work in manufacturing. 20% of the employees who do not work in manufacturing are women. What percent of the company's employees are men?

1. 50% of the company's male employees work in manufacturing
2. 20% of the company's employees who work in manufacturing are women

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Intern
Joined: 16 Feb 2006
Posts: 30

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Location: ZURICH

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30 Aug 2008, 09:47
Company employees = E
No. of working in manufacturing = 0.5E

Let no. of males are M and females are F.
therefore M+F = E

Female working manufacturing = F1
Female not working manufacturing= F2 = 0.2 x 0.5E = 0.1E
therefore F1 + F2 = F = F1 + 0.1E

Male working manufacturing = M1
Male not working manufacturing = M2 = 0.4E
therefore M1+M2=M=M1+0.4E

Statement 1. 50% of the company's male employees work in manufacturing
implies M1 = 0.5M
0.5M + M2 = M
= M2 = 0.5M = 0.4E
therefore M = 0.8E
80% of total company employees are male

Statement 2. 20% of the company's employees who work in manufacturing are women
F1 = 0.2E
F = 0.2E + 0.1E
= 0.3E
therefore no. of males = 0.7E
70% of total company employees are male .

option D
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Kudos [?]: 9 [0], given: 6

Manager
Joined: 12 May 2009
Posts: 53

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29 Nov 2009, 15:52
Quote:
80% of total company employees are male

Quote:
70% of total company employees are male .

How is it possible that we get two different percentages from the statements?

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Math Expert
Joined: 02 Sep 2009
Posts: 41891

Kudos [?]: 128977 [1], given: 12185

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29 Nov 2009, 17:06
1
KUDOS
Expert's post
enfinity wrote:
Quote:
80% of total company employees are male

Quote:
70% of total company employees are male .

How is it possible that we get two different percentages from the statements?

In DS two statements never contradict.

The problem is that for statement 2 solutions is not right.

Stem: consider total # of employees to be 100. We know that 50 are in manufacturing and 50 are not in manufacturing. From the 50 which are not in manufacturing, 40 are men.

(2) 20% of the company's employees who work in manufacturing are women. --> 40 (80%*50=40) are men in manufacturing. So total men 40+40=80, which is 80% of 100.

Hope its help.
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Manager
Joined: 12 May 2009
Posts: 53

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29 Nov 2009, 17:24
got it! good example. I misread the following part:

20% of the company's employees who work in manufacturing are women

Lesson Learned: Read the question properly and you save yourself a lot of frustration

Also, I'm using a double set matrix for this kind of problems for quite some time... that really increased my accuracy and timing on set problems... so if someone has trouble with this kind of problems, look into this concept!

Kudos [?]: 117 [0], given: 18

Manager
Joined: 22 Jul 2008
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Location: Bangalore,Karnataka

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30 Nov 2009, 06:55
even i got D

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Re: HOW MANY EMPLOYEES?   [#permalink] 30 Nov 2009, 06:55
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