It is currently 25 Nov 2017, 02:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Handshakes

Author Message
CIO
Joined: 09 Mar 2003
Posts: 460

Kudos [?]: 74 [0], given: 0

### Show Tags

14 Jul 2004, 07:16
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 4 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are 7 basketball teams at a tournament, each with 5 players. If each player will shake hands once with every other player not on his team, how many handshakes take place?

A) 324,632
B) 595
C) 525
D) 350
E) 120

Kudos [?]: 74 [0], given: 0

Joined: 31 Dec 1969

Kudos [?]: [0], given:

Location: Russian Federation
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 9: 740 Q49 V42
GMAT 11: 500 Q47 V33
GMAT 14: 760 Q49 V44
WE: Supply Chain Management (Energy and Utilities)

### Show Tags

14 Jul 2004, 07:38
ian7777 wrote:
There are 7 basketball teams at a tournament, each with 5 players. If each player will shake hands once with every other player not on his team, how many handshakes take place?

A) 324,632
B) 595
C) 525
D) 350
E) 120

There will be 6*5 = 30 handshakes with persons who are not members of one's team. Given that we have total 7*5 = 35 players, we get 30*35 handshakes. But each handshake in this pool of h/s is counted twice. Thus, we have to discount and the answer is 30*35/2 = 525, C.

Kudos [?]: [0], given:

Intern
Joined: 07 Jul 2004
Posts: 42

Kudos [?]: 39 [0], given: 0

### Show Tags

14 Jul 2004, 08:21
Different approach:

7C2*5C1*5C1=21*5*5=525

Kudos [?]: 39 [0], given: 0

Director
Joined: 05 May 2004
Posts: 574

Kudos [?]: 68 [0], given: 0

Location: San Jose, CA

### Show Tags

14 Jul 2004, 14:36
# of handshakes bween 2 teams = 5*5=25
# of comb to pick 2 teams = 7C2

Total comb = 25*7C2

Kudos [?]: 68 [0], given: 0

CIO
Joined: 09 Mar 2003
Posts: 460

Kudos [?]: 74 [0], given: 0

### Show Tags

14 Jul 2004, 23:13
OA is C. I agree with emmanuel's way most of all. very straight forward and easy to comprehend: 35x30/2.

Kudos [?]: 74 [0], given: 0

Intern
Joined: 07 Jun 2004
Posts: 29

Kudos [?]: [0], given: 0

Location: Sunnyvale

### Show Tags

15 Jul 2004, 14:50
Agreed, the combination method seems easy to mess up on, if you forget a factor to take into consideration. The dividing by two part is brilliant. Don't see that right off. Good job.
_________________

Davefor MBA

Kudos [?]: [0], given: 0

15 Jul 2004, 14:50
Display posts from previous: Sort by