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# Hard permutation/combination question

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Intern
Joined: 02 Jan 2003
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31 Oct 2003, 14:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

here is the question:
8 points lie on an xy plane. No more than 2 lie on the same line. How many triangles can you form with these points?

THANKS!!!
leon

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GMAT Instructor
Joined: 07 Jul 2003
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Location: New York NY 10024
Schools: Haas, MFE; Anderson, MBA; USC, MSEE

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01 Nov 2003, 03:49
you need to clarify this question. Are the triangles to be formed only with the given points as vertices? (i.e., are all of the sides of each triangle a complete segment from one point to another point?).

If so, i believe the answer is fairly straightforward....

56?
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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SVP
Joined: 03 Feb 2003
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03 Nov 2003, 05:33
8C3=56

Yes, but only if the points are the vertices of our triangles. Otherwise, the number of triangles is enormously more.

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03 Nov 2003, 05:33
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# Hard permutation/combination question

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