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Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. J
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Bunuel
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Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. J [#permalink] New post  29 Jan 2021, 07:45
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Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. Jack starts from the same point but at the speed of 90 miles/hr. At what time will jack be 120 miles, ahead of Harry ?

(A) 9:45 am
(B) 10:30 am
(C) 10:40 am
(D) 11:30 am
(E) 11:40 am
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Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. J [#permalink] New post  29 Jan 2021, 09:20
In 30 min, the distance covered by Harry \(=60*\frac{30}{60}=30\) miles

Jack has to cover the distance of \((120 + 30)\) miles relative to Harry with the relative speed of \((90 – 60)\) miles/hr = \(30\) miles/hr.

Time taken by Jack \(= \frac{150}{30}=5\) hr

5:30 AM+5 hr=10:30 AM

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Re: Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. J [#permalink] New post  29 Jan 2021, 09:43
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At 5:30 am, Harry has traveled for 30 minutes. Distance traveled = 60 * 0.5 = 30 miles

When Jack starts at 5:30, Harry is 30 miles away. Jack covers 90 - 60 = 30 miles over Harry every Hour.

So Jack has to cover a 30 mile gap and then another 120 miles over Harry, which is a total of 150 miles.

To this he will require 150 / 30 = 5 hours.

Therefore at 10:30 am, he will be 120 miles ahead of Harry.



Option B

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Re: Harry starts from A at a speed of 60 miles/hr at 5:00am. At 5:30 am. J [#permalink]
29 Jan 2021, 09:43
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