GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 21 Jun 2018, 07:28

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Hayden began walking from F to G, a distance of 40 miles

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Director
Director
avatar
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
Posts: 514
Location: United Kingdom
Concentration: International Business, Strategy
GMAT 1: 730 Q49 V45
GPA: 2.9
WE: Information Technology (Consulting)
Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post Updated on: 08 Sep 2013, 05:06
6
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

64% (01:48) correct 36% (02:02) wrong based on 323 sessions

HideShow timer Statistics

Hayden began walking from F to G, a distance of 40 miles, at the same time Ava began walking from G to F on the same road. If Hayden’s walking speed was x miles per hour and Ava’s was y miles per hour, how many miles away from F were they, in terms of x and y, when they met?

(A) \(\frac{40(x-y)}{x+y}\)
(B) \(40x-\frac{y}{x+y}\)
(C) \(\frac{(x-y)}{x+y}\)
(D) \(\frac{40y}{x+y}\)
(E) \(\frac{40x}{x+y}\)

Ok. This is how I am solving this.

Hayden's speed = x miles/hr
Ava speed = y miles/hr

Relative speed = (x+y) miles/hr as they are travelling in opposite direction (F to G and G to F)

Total time taken = \(\frac{40}{x+y}\) ---------------------------[D = Speed/Time]

So Hayden will take = \(\frac{40x}{x+y}\)-------------------------[I have guessed this and this is the right answer]. But not 100% why though? Can someone please help?

_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610
GMAT ==> 730


Originally posted by enigma123 on 04 Mar 2012, 13:14.
Last edited by Bunuel on 08 Sep 2013, 05:06, edited 1 time in total.
Edited the question.
Retired Moderator
User avatar
B
Joined: 10 May 2010
Posts: 813
GMAT ToolKit User Premium Member
Re: Hayden & Eva [#permalink]

Show Tags

New post 04 Mar 2012, 14:21
Total time(T) taken is the time for Hayden and Eva to meet. Now you know that Hayden must tavel for time T before they meet. Thus distance Hayden will cover is = Time T * Hayden Speed.
_________________

The question is not can you rise up to iconic! The real question is will you ?

Expert Post
2 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 46251
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 04 Mar 2012, 16:05
2
4
Hayden began walking from F to G, a distance of 40 miles, at the same time Ava began walking from G to F on the same road. If Hayden’s walking speed was x miles per hour and Ava’s was y miles per hour, how many miles away from F were they, in terms of x and y, when they met?
(A) \(\frac{40(x-y)}{x+y}\)
(B) \(\frac{40(x-y)}{x+y}\)
(C) \(\frac{(x-y)}{x+y}\)
(D) \(\frac{40y}{x+y}\)
(E) \(\frac{40x}{x+y}\)

Combined rate of Hayden and Ava is \(x+y\) miles per hour, hence they will meet in \(time=\frac{distance}{rate}=\frac{40}{x+y}\) hours. In \(\frac{40}{x+y}\) hours Hayden will cover \(distance=rate*time=x*\frac{40}{x+y}\) miles.

Answer: E.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Director
Director
avatar
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
Posts: 514
Location: United Kingdom
Concentration: International Business, Strategy
GMAT 1: 730 Q49 V45
GPA: 2.9
WE: Information Technology (Consulting)
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 04 Mar 2012, 16:07
Thanks Bunuel. But why we are only calculating it for Hayden? That's where I am getting confused buddy.
_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610
GMAT ==> 730

Expert Post
1 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 46251
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 04 Mar 2012, 16:14
1
enigma123 wrote:
Thanks Bunuel. But why we are only calculating it for Hayden? That's where I am getting confused buddy.


Hayden began walking from F and we are asked how many miles away from F were Hayden and Ava when they met. In 40/(x+y) hours Hayden, at x miles per hour, will cover 40/(x+y)*x miles from F.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Manager
Manager
avatar
Joined: 26 Jul 2012
Posts: 63
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 07 Sep 2013, 19:52
This is a confusing problem - especially if someone assumes x = y, then choice D is also valid.
Expert Post
Director
Director
User avatar
B
Joined: 17 Dec 2012
Posts: 635
Location: India
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 07 Sep 2013, 21:54
1. Time taken for the two to meet which is also the time walked by Hayden = 40 /x+y hrs
2. Speed of Hayden = x miles/hr
3. Distance traveled by Hayden = 40x / (x+y)
_________________

Srinivasan Vaidyaraman
Sravna
http://www.sravnatestprep.com/best-online-gre-preparation.php

Improve Intuition and Your Score
Systematic Approaches

Senior Manager
Senior Manager
User avatar
Joined: 13 May 2013
Posts: 430
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 09 Sep 2013, 03:06
Hayden began walking from F to G, a distance of 40 miles, at the same time Ava began walking from G to F on the same road. If Hayden’s walking speed was x miles per hour and Ava’s was y miles per hour, how many miles away from F were they, in terms of x and y, when they met?

combined speed = x+y miles/hour

time in which it took them to meet = 40/x+y

So, we know that it takes them 40/x+y hours to meet up. The question states that Hayden traveled from F to G and Ava, from G to F. It asks us how far from F (Hayden's starting point) did they meet at. Therefore, to solve for distance (d=r*t) we solve by multiplying Hayden's rate (x) by the time it took them to meet (40/x+y) to get 40x/x+y

ANSWER: E
Manager
Manager
avatar
Joined: 28 Aug 2013
Posts: 92
Location: India
Concentration: Operations, Marketing
Schools: Insead '14, ISB '15
GMAT Date: 08-28-2014
GPA: 3.86
WE: Supply Chain Management (Manufacturing)
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 22 Apr 2014, 07:10
Bunuel wrote:
enigma123 wrote:
Thanks Bunuel. But why we are only calculating it for Hayden? That's where I am getting confused buddy.


Hayden began walking from F and we are asked how many miles away from F were Hayden and Ava when they met. In 40/(x+y) hours Hayden, at x miles per hour, will cover 40/(x+y)*x miles from F.


Still much is left in explanation :

Ans you will get will be same if you multiply Ava rate with time when they meet :

As Distance travel by ava when they meet : y* 40/(x+y)

Now question has asked distance from F i.e. you have to subtract distance travel by ava from 40.

therefore - 40 - (40y/x+y) = on solving you will get 40x/x+y i.e E

Hope i make it clear
_________________

G-prep1 540 --> Kaplan 580-->Veritas 640-->MGMAT 590 -->MGMAT 2 640 --> MGMAT 3 640 ---> MGMAT 4 650 -->MGMAT 5 680 -- >GMAT prep 1 570

Give your best shot...rest leave upto Mahadev, he is the extractor of all negativity in the world !!

SVP
SVP
User avatar
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1837
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 24 Apr 2014, 01:26
Refer diagram below;

We require to find d (in terms of x & y) (how many miles away from F were they)

Setting up the equation

\(\frac{d}{x} = \frac{40-d}{y}\)

(x+y)d = 40x

\(d = \frac{40x}{x+y}\)

Answer = E
Attachments

spe.jpg
spe.jpg [ 17.1 KiB | Viewed 2896 times ]


_________________

Kindly press "+1 Kudos" to appreciate :)

SVP
SVP
User avatar
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1837
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 24 Apr 2014, 01:27
minkathebest wrote:
This is a confusing problem - especially if someone assumes x = y, then choice D is also valid.



Please refer diagram above. There should be no confusion after :)
_________________

Kindly press "+1 Kudos" to appreciate :)

Intern
Intern
avatar
B
Joined: 09 Nov 2015
Posts: 30
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 18 Nov 2016, 22:33
F------------------------M-------------------------------G
Hayden-----> <------Ava

Hayden starts from Point F, Ava from Pt G and they meet at Pt M. Since the question is "how far from F do they meet", we are required to figure out FM i.e. the distance that Hayden covers [this should answer Enigma123's question]. Since they start walking towards each other at the same time and continue walking until they meet, they take the same amount of time to cover their respective distances [FM miles by Hayden and GM miles by Ava]. Therefore, the ratio of their speeds is equal to that of the distances they cover until they meet. T/4, FM:GM=x:y. Since [FM+GM]=40 miles, FM=40x/[x+y]. Ans:E.
Intern
Intern
avatar
Joined: 06 Oct 2016
Posts: 20
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 23 Nov 2016, 06:30
Can we get this answer by plugging in some values

Sent from my A1601 using GMAT Club Forum mobile app
Intern
Intern
avatar
B
Joined: 09 Nov 2015
Posts: 30
Re: Hayden began walking from F to G, a distance of 40 miles [#permalink]

Show Tags

New post 23 Nov 2016, 22:09
ashishahujasham
Yes, we can. Let's assume x=20 mph and y=60 mph. Then, FM:GM=20:60=1:3. That is, FM (distance covered by Hayden) is 1/4th the total distance (40 miles). T/4, FM=10 miles. Now, lets plug in the assumed values of 'x' &'y' in FM=40x/(x+y):
40x20/(20+60)=800/80=10 miles.
I am not sure from your question if that is what you needed explained. If so, glad to have been able to help.
Re: Hayden began walking from F to G, a distance of 40 miles   [#permalink] 23 Nov 2016, 22:09
Display posts from previous: Sort by

Hayden began walking from F to G, a distance of 40 miles

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.