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Henry eats X scones in X percent of the time it takes Rachel
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20 Jul 2014, 02:55
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Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
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20 Jul 2014, 05:51
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goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Let x=y=10.
So, Henry eats 10 scones in 10% of the time it takes Rachel to eat 10 scones. This means that Henry eats 10 times as fast as Rachel.
Rachel eats 4 scones in 10 minutes --> 8 scones in 20 minutes. Henry will take 20/10 = 2 minutes to eat 8 scones.
Plug y = 10 into the options to see which one of them gives 2. Only A fits.
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20 Jul 2014, 20:30
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
If Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones.
Then, X = 50 , Y = 100
Rachel eats 4 cones in 10 minutes
=
Rachel eats 1 cone in 5/2 minutes Rachel eats 100 cones in 250 minutes
Since Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones = 250/2 = 125 minutes
Henry eats 50 cones in 125 minutes Henry eats 8 cones in 20 minutes
Both options A & D give the answer 20 when values are plugged in
Is the question right, or should we change our plugged values if such a situation arises?
Re: Henry eats X scones in X percent of the time it takes Rachel
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20 Jul 2014, 20:35
Bunuel wrote:
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Let x=y=10.
So, Henry eats 10 scones in 10% of the time it takes Rachel to eat 10 scones. This means that Henry eats 10 times as fast as Rachel.
Rachel eats 4 scones in 10 minutes --> 8 scones in 20 minutes. Henry will take 20/10 = 2 minutes to eat 8 scones.
Plug y = 10 into the options to see which one of them gives 2. Only A fits.
Answer: A.
If Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones.
Then, X = 50 , Y = 100
Rachel eats 4 cones in 10 minutes
=
Rachel eats 1 cone in 5/2 minutes Rachel eats 100 cones in 250 minutes
Since Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones = 250/2 = 125 minutes
Henry eats 50 cones in 125 minutes Henry eats 8 cones in 20 minutes
Both options A & D give the answer 20 when values are plugged in
Re: Henry eats X scones in X percent of the time it takes Rachel
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21 Jul 2014, 11:59
hamzakb wrote:
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
If Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones.
Then, X = 50 , Y = 100
Rachel eats 4 cones in 10 minutes
=
Rachel eats 1 cone in 5/2 minutes Rachel eats 100 cones in 250 minutes
Since Henry eats 50 cones in 50% of time it takes Rachel to eat 100 cones = 250/2 = 125 minutes
Henry eats 50 cones in 125 minutes Henry eats 8 cones in 20 minutes
Both options A & D give the answer 20 when values are plugged in
Is the question right, or should we change our plugged values if such a situation arises?
For plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.
_________________
Henry eats X scones in X percent of the time it takes Rachel
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Updated on: 28 Nov 2015, 13:29
rachel eats Y scones in 5Y/2 minutes henry eats X scones in (X/100)(5Y/2)=XY/40 minutes henry's rate=X/(XY/40)=40/Y scones per minute henry's time for eating 8 scones=8/(40/Y)=Y/5 minutes
Originally posted by gracie on 14 Nov 2015, 22:29.
Last edited by gracie on 28 Nov 2015, 13:29, edited 1 time in total.
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14 Nov 2015, 23:12
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Hi, R eats Y scones ,say in Z minutes.. so R will eat 4 cones in 4Z/Y but this is equal to 10 min so 4z/y=10 or Z=5Y/2 thus R will eat 8 in 5Y..
now lets see H.. H eats X scones in X% of time R takes, which is 5Y/2 or X scones in X/100*5Y/2=XY/40.. so H eats 8 scones in 8*XY/40(X)=Y/5 ans A
_________________
Re: Henry eats X scones in X percent of the time it takes Rachel
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07 May 2017, 05:13
chetan2u wrote:
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Hi, R eats Y scones ,say in Z minutes.. so R will eat 4 cones in 4Z/Y but this is equal to 10 min so 4z/y=10 or Z=5Y/2 thus R will eat 8 in 5Y..
now lets see H.. H eats X scones in X% of time R takes, which is 5Y/2 or X scones in X/100*5Y/2=XY/40.. so H eats 8 scones in 8*XY/40(X)=Y/5 ans A
Re: Henry eats X scones in X percent of the time it takes Rachel
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07 May 2017, 06:39
ShashankDave wrote:
chetan2u wrote:
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Hi, R eats Y scones ,say in Z minutes.. so R will eat 4 cones in 4Z/Y but this is equal to 10 min so 4z/y=10 or Z=5Y/2 thus R will eat 8 in 5Y..
now lets see H.. H eats X scones in X% of time R takes, which is 5Y/2 or X scones in X/100*5Y/2=XY/40.. so H eats 8 scones in 8*XY/40(X)=Y/5 ans A
Is there a problem with the wording? I didn't get a clue how the answers have come, because the wording is kind of weird for me.
Hi,
The wording is fine but complicated which would be very rare in actuals.
You can actually combine first two sentences to get, Henry eats x scones in x%of 10 minutes in which Rachel eats 4 scones. In how much time will Henry eat 8 scones.
And if you combine further and want to remove x too.. Henry eats 1 scones in 1% of 10 minutes in which Rachel eats 4 scones. In how much time will Henry eat 8 scones.
Now answer is straight ... Henry will eat 8 in 8% of 10 minutes, so \(\frac{8}{100}*10=\frac{8}{10}\) or 4/5 minutes...
Now y here is 4, substitute and straight A is the answer..
_________________
Henry eats X scones in X percent of the time it takes Rachel
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Updated on: 15 Jan 2018, 23:23
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
We know that \(Rate * Time = Work\) --- 1 Consequently \(Time = \frac{Work}{Rate}\) -- 2 and \(Rate = \frac{Work}{Time}\) -- 3
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Re: Henry eats X scones in X percent of the time it takes Rachel
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18 Jan 2018, 14:26
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
The rate of Rachel is 4/10 = 2/5.
If we let X = 10 and Y = 4, we see that Henry eats 10 scones in 10% of the time it takes Rachel to eat 4 scones. Since Rachel eats 4 scones in 10 minutes and 10% of 10 minutes is 1 minute, that means Henry eats 10 scones in 1 minutes. If we let m = the number of minutes Henry eats 8 scones, we set up the proportion:
10/1 = 8/m
10m = 8
m = 8/10 = 4/5
Thus, Henry eats 8 scones in 4/5 of a minute. However, since Y = 4, Henry eats 8 scones in Y/5 minutes.
Re: Henry eats X scones in X percent of the time it takes Rachel
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15 Jan 2019, 11:20
Top Contributor
goodyear2013 wrote:
Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following?
A. Y/5 B. 320/Y C. 100Y/(5X) D. XY/250 E. Y/(5X)
Let's use the INPUT-OUTPUT approach. Let's assign some values of X and Y so that they satisfy the information in the question.
Let X = 25. This means Henry eats 25 scones in 25 percent of the time it takes Rachel to eat Y scones Let Y = 100. This means Henry eats 25 scones in 25 percent of the time it takes Rachel to eat 100 scones Notice that this implies Rachel and Henry eat at the SAME RATE. Here's why: If Henry eats 25 scones in 1/4 the time it takes Rachel to eat 100 scones, then if we quadruple Henry's eating time, then he will eat 100 scones in the SAME TIME it take Rachel to each 100 score.
If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 8 scones must be equal to which of the following? Henry is going to eat TWICE as many scones as Rachel. Since Henry and Rachel eat at the SAME RATE, the time it takes Henry to eat 8 scones will be TWICE the time it takes Rachel to each 4 scones. So it will take Henry 20 minutes to eat 8 scones
So, when X = 25 and Y = 100, the answer to the question (aka the OUTPUT) will be 20
Now check the answer choices to see which one yields an OUTPUT of 20 when we INPUT X = 25 and Y = 100 A. Y/5 = 100/5 = 20. Perfect! KEEP A B. 320/Y = 320/100 = 3.2. No good. We want an output of 20 C. 100Y/(5X) = (100)(100)/(5)(25) = 80. No good. We want an output of 20 D. XY/250 = (100)(25)/250 = 10. No good. We want an output of 20 E. Y/(5X) = (100)/(5)(25) = 0.8. No good. We want an output of 20