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# Here is another one that I had trouble with

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Manager
Joined: 01 Apr 2006
Posts: 179

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19 Aug 2006, 08:19
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Difficulty:

(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Here is another one that I had trouble with.
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Kudos [?]: 126 [0], given: 0

Manager
Joined: 01 Apr 2006
Posts: 179

Kudos [?]: 126 [0], given: 0

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19 Aug 2006, 08:21
Should I assume that there are no other types of animals on the farm other than pigs or cows?

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Intern
Joined: 18 Aug 2006
Posts: 21

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19 Aug 2006, 08:51
The stem tells you that there are 2/3 of 60 total animals that are either pigs or cows = 40 pigs or cows.

1) 2*C (> than) + P = 40 This by itself isn't enough.

2) P > 12, when combined with the first statement, p must be at least 13 which means C must be at least 27.

So 27+13 = 40, there are no other possibilities. So C is correct.

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Manager
Joined: 01 Apr 2006
Posts: 179

Kudos [?]: 126 [0], given: 0

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22 Aug 2006, 06:29
The OA is C.

Thanks Mathec for contributing to this question

I had misread the question to mean that there are either 40 cows or 40 pigs grrr....

Cheers,
jjhko

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Current Student
Joined: 29 Jan 2005
Posts: 5210

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22 Aug 2006, 06:40
Tricky wording.

If statement 1 were to read: The farm has twice as many cows as pigs, then it would be sufficient.

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22 Aug 2006, 06:40
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