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# Heres a strange one.... If y is a positive integer, is 3y

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Heres a strange one.... If y is a positive integer, is 3y [#permalink]

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22 Apr 2006, 23:30
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Heres a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.
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22 Apr 2006, 23:42

1. y+319 = even, hence y is odd (odd + odd --> even). Thus 3y = oddxodd = odd!

2. Y is not an odd number. If it is odd, then Y should be divisible by 1 and by itself which is also odd!. But it says it is not divisble by any odd number, save 1. Thus it has to be even. Thus the 3x even = even!

Usually in GMAT both the options are congruent, ie they yield the same results. Here option 1 seems to indicate odd, while option 2 seems to indicate even! Thats kind of Weird for GMAT.

Where did you get this Q from? I have not seen this one in Kaplan though, which Kaplan is it?
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Re: WEIRD Kaplan DS [#permalink]

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23 Apr 2006, 07:54
GMATT73 wrote:
Heres a strange one....
If y is a positive integer, is 3y odd?
1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

since y is a +ve integer,
from i, y is odd. so suff..
from ii, y is 1. also suff.

if y = 2, then 2 is evenly divided by 1 and 2. so only integer that is evenly (i guess evenly here doesnot mean 2, 4, 6 or so on) divided only by 1 is 1.

great question. D.
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Re: WEIRD Kaplan DS [#permalink]

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23 Apr 2006, 21:12
Professor wrote:
GMATT73 wrote:
Heres a strange one....
If y is a positive integer, is 3y odd?
1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

since y is a +ve integer,
from i, y is odd. so suff..
from ii, y is 1. also suff.

if y = 2, then 2 is evenly divided by 1 and 2. so only integer that is evenly (i guess evenly here doesnot mean 2, 4, 6 or so on) divided only by 1 is 1.

great question. D.

Great explanation professor.
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23 Apr 2006, 21:58
Well, it says it cannot be evenly divided by any ODD integer other than 1. So it may well be divisible by 2.

A
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24 Apr 2006, 03:39
Maxi2006 wrote:
Well, it says it cannot be evenly divided by any ODD integer other than 1. So it may well be divisible by 2.

A

Be careful, evenly divided means divided without a remainder.

So the answer is 'D'.
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24 Apr 2006, 06:47
Here is the confusing part with the wording in statement 2.

---> y can either be 1 or an even number (2, 4, 8 ...) because they all divide evenly.

** If y = 1, then the answer to the stem is a definate YES.

<but>

** If y is an even number (also divisible by 1), then the answer to the stem is a definate NO.

Given these two possible conditions, how can both statements be sufficient (D)

BTW: This is from the "2005 Borders Exclusive Edition" Kaplan prep text.

Last edited by GMATT73 on 24 Apr 2006, 07:22, edited 2 times in total.
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Re: WEIRD Kaplan DS [#permalink]

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24 Apr 2006, 07:12
GMATT73 wrote:
Heres a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

statement 2 means y is divisible by one and only one odd number that is 1.
--> y can be 1 and 2 ( 4, 8 and all exponents of 2)
--> 3y can be either odd or even
--> insuff

A it should be.
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24 Apr 2006, 07:17
D is the answer.

From 1st option > we get 3y is odd
from 2nd option > y is even and 3y is even so suff.
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24 Apr 2006, 07:20
but from statement 2, y can also be 1
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24 Apr 2006, 07:28
Thanks for backing me up here Laxie Any other input guys?
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24 Apr 2006, 14:17
I agree. y=1 satisfies the second condition so we don't really know if 3y is odd or even for that one. In other word the answer should be A.
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24 Apr 2006, 14:35
yes the answer should be A

for B 1 and all other even numbers can satisfy the criteria ...
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24 Apr 2006, 19:09
3y is odd only if y is odd. So the question si asking if y is odd.

1) y+319 is even. 319 is odd. So y must be odd. Sufficient.

2) y is prime, which could be odd (any primes other than 2) or not odd(the prime number 2). Insufficient.

Ans A
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Re: WEIRD Kaplan DS [#permalink]

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24 Apr 2006, 20:57
GMATT73 wrote:
Heres a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

good question...what is the OA?
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24 Apr 2006, 22:44
I read ii to mean y is prime as well but since it does not exclude 2 than it is not suff so A
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25 Apr 2006, 21:41
The OA, according to Kaplan is (D). I am still not convinced...
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25 Apr 2006, 22:20
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...

But as we know, Kaplan is sometimes very erroneous
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25 Apr 2006, 22:31
laxieqv wrote:
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...

But as we know, Kaplan is sometimes very erroneous

buddy, our math experts has cleared the confusion and misconception that D is not correct.
it was indeed a great discussion.
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25 Apr 2006, 22:44
Professor wrote:
laxieqv wrote:
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...

But as we know, Kaplan is sometimes very erroneous

buddy, our math experts has cleared the confusion and misconception that D is not correct.
it was indeed a great discussion.

buddy, this time, the merit goes to Matt as he pointed out the confusion and put forward a thorough consideration
If we stay alert like Matt, keeping an eye on any trickiness of GMAT, we'll certainly ace the maths section
25 Apr 2006, 22:44

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# Here`s a strange one.... If y is a positive integer, is 3y

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