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Hillary and Eddy are climbing to the summit of Mt. Everest from a base

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Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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19 Aug 2015, 22:24
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75% (02:20) correct 25% (02:50) wrong based on 205 sessions

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Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,800 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 800 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?

A) 11:00
B) 12:00
C) 12:30
D) 15:00
E) 16:00

Kudos for a correct solution.

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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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19 Aug 2015, 22:37
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Bunuel wrote:
Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,800 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 800 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?

A) 11:00
B) 12:00
C) 12:30
D) 15:00
E) 16:00

Ans: B

Solution:H stopped 800 ft before reaching the final point, time taken to reach 4000 ft= 4000/800= 5hrs.
this means she reached there at 11:00.

speed difference between them is 800-500=300 ft/hr
so by the time H stops they have 1500 ft of distance

so now here we use relative speed formula they both are travelling toward each other with speed of 1000 and 500 total 1500 ft/hr and distance bwn them is 1500 ft so time taken to meet = 1 hr from 11:00
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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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19 Aug 2015, 22:40
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Bunuel wrote:
Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,800 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 800 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?

A) 11:00
B) 12:00
C) 12:30
D) 15:00
E) 16:00

Kudos for a correct solution.

Is it B ?
I got B .

I did it like this :

hillary stopped at 4000 ft.
Took her 4000/800 = 5 hours.
So in 5 hours eddy will be at 5 * 500 = 2500 ft.

difference = 1500 ft.

Formula used :

1.distance between the two =1500
2. as both are moving in opposite directions so , speeds will be added

time when both pass each other : distance between the two points / sum of the speeds

= 1500 / (1000+500 )
= 1 hour.

now started at 6:00 .
so after 5 hours at 4000ft .(calculated above)
then
after 1 hour they meet : so 12:00.

Hope i am right.!
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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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21 Aug 2015, 05:36
1
Bunuel wrote:
Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,800 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 800 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?

A) 11:00
B) 12:00
C) 12:30
D) 15:00
E) 16:00

Kudos for a correct solution.

Speed of H=800 ft/hour and Speed of E=500 ft/hour
When H has covered 4000 ft, she has traveled for 5 hours, time is 11 AM(6AM+5 hours)
At this time, E has covered 500*5=2500 ft
Now, when H drops at the rate of 1000 ft/hour, at 12 noon, H is at 3000 feet and E is also at 3000 feet since he has covered 500 feet more in this one hours
Math Expert
Joined: 02 Sep 2009
Posts: 52344
Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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23 Aug 2015, 10:35
Bunuel wrote:
Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,800 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 800 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?

A) 11:00
B) 12:00
C) 12:30
D) 15:00
E) 16:00

Kudos for a correct solution.

Economist GMAT Tutor Official Solution:

Begin by finding the duration of Hillary’s climb. If she stopped 800 ft short of the summit, she climbed a total of 4,000 ft (4,800 to the summit minus 800). At a rate of 800 ft/hr, she would have climbed for five hours. Thus, Hillary stops climbing and begins her descent at 11:00.

Next, we can find the distance between Hillary and Eddy at the end of her climb by multiplying the difference in their climbing speeds, 300 ft/hr, by five hours. So, we know that the two are 1,500 ft apart when Hillary begins her descent.

Finally, we calculate the time it would take the two to cover the 1,500 ft distance at a combined rate of 1,500 ft/hr (1,000 ft/hr descent plus 500 ft/hr climb). So, Hillary and Eddy meet up at 12:00, one hour after she begins her descent.
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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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14 Nov 2015, 20:40
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formula: time=distance/speed
hillary takes 5 hours to reach 4000 miles and by the meantime eddy reaches 2500 miles
distance between eddy and hillary=4000-2500=1500
relative speed=1000+500=1500
they take more 1500/1500 or 1 hour to meet
total time=5+1=6
clock time: 6.00+6=12.00
Ans: B
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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base  [#permalink]

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25 Dec 2017, 23:55
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Re: Hillary and Eddy are climbing to the summit of Mt. Everest from a base &nbs [#permalink] 25 Dec 2017, 23:55
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