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How long did it take Carlos to drive nonstop from his home [#permalink]

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15 Mar 2012, 14:13

11

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00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

56% (00:51) correct
44% (00:48) wrong based on 446 sessions

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How long did it take Carlos to drive nonstop from his home to Atlanta, Georgia?

(1) Carloss average speed for the trip was 55 miles per hour. (2) If Carloss average speed for the trip had been 20 percent faster, the trip wouldve taken 3 hours.

Statement 1 We dont know the distance so we cannot calculate T

Statement 2 IF we apply ratios we can solve it easily. New velocity is 1.2 (6/5) times the old velocity i.e if velocity has increased 6/5 times then time to cover the same distance will reduce to 5/6 times. so we can write that 5/6T(old time taken)=3(new time taken) so T(old)=3.6 hrs

so from statement 2 we know the time taken so the ANS is B

How long did it take Carlos to drive nonstop from his home to Atlanta, Georgia?

Distance=Rate*Time

(1) Carloss average speed for the trip was 55 miles per hour --> Rate=55 miles per hour, we still need Distance to get Time. Not sufficient.

(2) If Carloss average speed for the trip had been 20 percent faster, the trip wouldve taken 3 hours --> notice that we are dealing with the SAME distance: Distance=Rate*Time=(1.2*Rate)*3 --> Rate*Time=(1.2*Rate)*3 --> Time=3.6 hours. Sufficient.

Re: How long did it take Carlos to drive nonstop from his home [#permalink]

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24 May 2016, 22:56

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Re: How long did it take Carlos to drive nonstop from his home [#permalink]

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06 Dec 2016, 15:43

enigma123 wrote:

How long did it take Carlos to drive nonstop from his home to Atlanta, Georgia?

(1) Carloss average speed for the trip was 55 miles per hour. (2) If Carloss average speed for the trip had been 20 percent faster, the trip wouldve taken 3 hours.

1 is clearly insufficient.

2. let's give some letters for rate, time distance. RT = D, where R=rate, T=time, D=distance. we are given: 1.2R * (T-3) = RT 1.2RT - 3.6R = RT 3.6R = 0.2RT | divide by R 3.6 = 0.2T we can find T. sufficient.