How many 5 digit numbers can be created if the following

I got 2688..

Following is my calculation:

First digit can be 2,4,6,8
2nd digit can be 1,3,5,7,9
3rd digit can be 3,5,7

Notice that 2nd and 3rd digit have same numbers thus there is a possibilty of repeat numbers. Only 1 and 9 are not repeated.
Thus 4*2*3*7*6 =1008 (This considers the case when 2nd digit is 1 or 9)
Now consider the second case where the second digit is 3, 5 or 7. In this scenario 2nd and 3rd digit can be same.
Thus we get 2 equations, one when the number repeats and the other when the number doesn't repeat
4*3*2*7*6 =1008 (2nd digit is 3,5,7 and 3rd digit is different than 2nd)
4*3*1*8*7 =672 (2nd digit is 3,5,7 and 3rd digit is same as 2nd)
Adding 1008+1008+672= 2688
Hence the Answer