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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?

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Intern  B
Joined: 25 Aug 2015
Posts: 44
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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As y can be negative of positive for absolute value to hold, then any 2 values for y.

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Manager  G
Joined: 30 May 2018
Posts: 161
GMAT 1: 710 Q49 V36 GPA: 3.8
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1

Take four possible cases of y, i.e, y<-8, -8<y<-3, -3<y<4 and y>4. In each case, solve the equation, y gets a value outside of assumed range of each case.
Senior Manager  P
Joined: 31 May 2018
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Location: United States
Concentration: Finance, Marketing
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
here the solution of the question
Attachments got.png [ 33.65 KiB | Viewed 548 times ]

Intern  B
Joined: 05 Jun 2018
Posts: 33
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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Four scenarios

4>y>0

y+3=y+8+4-y
y=9

Not possible

y>4

y+3=8+y+y-4
y=-1

Not possible

y<-8
-y-3=-y-8+4-y
y=-1
Not possible

-3>y>-8
-y-3=8+y+4-y
y=-15
Not possible

0>y>-3
y+3=8+y+4-y
y=9

Not possible

Thus, 0 values
Manager  S
Joined: 12 Mar 2018
Posts: 82
Location: United States
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
It took me way too long to solve this problem (3m and 46s)

I followed the 3 step approach explained in the Absolute Value theory here (https://gmatclub.com/forum/math-absolut ... 86462.html), and got the answer 0, which is option A.

But obviously from the time standpoint, close to 4 mins is terrible for this kind of question.
Can one of the experts help me with a quicker/alternate solution that can be done in less than 2 mins?

Here are the details of what I did:

Step 1: Identified the critical points, -8, -3 and 4 and set conditions, y < -8, -8 <= y < -3, -3 <= y < 4, and y >= 4
Step 2: For each one of the regions listed in step 1, used conditions to open modulus and solve for y
Step 3: Checked if the resulting y value falls within the region for each one of the ranges in Step 1. None of the y values did, so the answer is 0
Manager  S
Joined: 06 Aug 2018
Posts: 97
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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Basically there can be different combinations made

Firstly all r positive

1
|y+3|=|8+y|+|4−y|

y+3=8+y+4-y
y=9

Putting 9 in equation
Both sides are not equal

2. If one is negative

y+3=-8-y+4-y
y=-7/3

This satisfies the eqaution

3 both negative

y+3=-y-8-4+y
y=-15

Again this doesn't satify

Now -y-3=y-8+4-y
y=1 again this doesn't satisfy equation ,

Then -y-3=-y-8+4-y
y=-1

Then -y-3=-y-8-4+y
y=9

This again doesn't satisfy

There is only one solution as -7/3

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Senior Manager  G
Joined: 04 Apr 2015
Posts: 254
GMAT 1: 650 Q49 V31
GPA: 3.59
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
firstly analyzing the problem i was confused whether to plug in or form equation with cases '

however
considering the equation
|y+3|=|8+y|+|4−y|
let A= |y+3|
B= |8+y|
C=|4−y|

A is always positive : or zero
B is always positive or zero
C is always positive or zero

lets compare A and B
|y+3|=|8+y|they can never be equal distance of one number and 3 on number line cannot be equal to distance of same number and 8 so no value exists

adding C to the equation further complicates the issue as C is positive and distance of B and C together cannot be equal to A

so answer A : no value exist
Director  P
Joined: 18 May 2019
Posts: 661
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
|y+3|=|8+y|+|4-y|
The center points can be gotten by equating the absolute values to zero. Hence the key points are -3, -8 and 4.
The possible conditions are
y<-8; -8<=y<-3; -3<=y<4; and y>=4.
When y<-8,
-(y+3)=-(8+y)+(4-y)
Solving for y yields y=-1
Since -1 does not fit into the range of values y<-8, we reject this solution.
When -8<=y<-3,
-(y+3)=(8+y)+(4-y)
y=-15. -15 does not fall within the above range hence we reject this solution as well.
-3<=y<4;
(y+3)=(8+y)+(4-y)
Solving for y, y=9. And nine falls outside the range, hence we reject this solution as well.
y>=4
(y+3)=(8+y)-(4-y)
y=1, which is not greater than 4, hence we reject this solution as well.
This means there is no solution to this equation. Hence choice A is the right answer.

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Manager  G
Joined: 06 Feb 2019
Posts: 114
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
there is no such y that will match the equation:
positive numbers are out because |y+3| will be always less that |8+y| (keeping in mind that |4-y| may not be negative.
zero is out
negative numbers will make |4-y| big positive number

Manager  G
Joined: 12 Jan 2018
Posts: 117
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
This equation has 3 critical points, -3,-8, 4. Hence, 4 conditions to check.

1. y>4
(y+3)=(8+y)-(4-y) Since, |x|=x if x>/=0. |x|=-x if x<0
y=-1 , but condition is y>4. No solution in this range

2. -3<y</=4
(y+3)=(8+y)+(4-y)
y=11, outside the range. No solution

3.- -8<y</=-3
-(y+3)=(8+y)+(4-y)
y=-15
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Manager  G
Joined: 30 Nov 2017
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WE: Consulting (Consulting)
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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Explanation
Given; |y+3| = |8+y| + |4-y|
Solving for y;
Condition 1
y+3 = 8+y+4-y
This gives; y = 9
Testing y = 9 in the equation above
We have; |9+3| = |8+9| + |4-9|
Thus, 12 = 17 - 5
Therefore, 12 = 12 (y=9 satisfies the equation)
Condition 2
If we negate the left side of the equation, we have
-y-3 = 8+y+4-y
This gives; y=-15
Testing y=-15 in the original equation
We have; -15+3 = 8-15+4+15
-12 = 12 (y = -15 does not satisfy the equation)
Condition 3
Negating only one side of the equation on the right side, we have
y+3 = 8+y - (4-y)
y+3 = 8+y-4+y
y+3 = 4+2y
Thus, y=-1
Testing y=-1 in the original equation
We have; -1+3 = 8-1 + 4+1
2 = 12 (y=-1 does not satisfy the equation)
Therefore, the equation has only one solution and it's answer choice B.

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Manager  G
Joined: 28 Jan 2019
Posts: 130
Location: Peru
GMAT 1: 640 Q49 V29
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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1
There are 4 ranges:
Y≤ -8, Y =-1
-8≤Y≤-3, Y= -15
-3≤Y≤4, Y = 15
Y≥4, Y = -1

So, none of them comply with the ranges, so (A)

None of them satisfy the equation, so (A)
Intern  B
Joined: 12 Jul 2014
Posts: 3
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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C - 2 values possible
Intern  B
Joined: 22 Jun 2019
Posts: 41
Concentration: Operations, Organizational Behavior
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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tried plugging in several numbers and realized it never matches so A)
Manager  G
Joined: 08 Jan 2018
Posts: 129
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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The three critical values are -8, -3 and 4

We can have 4 conditions:

1. y < -8:
-(y + 3) = - (8 + y) + (4 – y)
=> y = -1
This does not fall in the range of y < -3. Therefore, we can reject the solution.

2. -8 <= y < -3:
-(y + 3) = (8 + y) + (4 – y)
=> y = -15
This does not fall in the range of -8 <= y < -3. Therefore, we can reject the solution.

3. -3 <= y <4
(y + 3) = (8 + y) + (4 – y)
=> y = 9
This does not fall in the range of -3 <= y <4. Therefore, we can reject the solution.

4. y >= 4
(y + 3) = (8 + y) – (4 – y)
=> y = -1
This does not fall in the range of y >= 4. Therefore, we can reject the solution.

Therefore, no value of y satisfy. Answer A.
Director  V
Joined: 30 Sep 2017
Posts: 590
GMAT 1: 720 Q49 V40 GPA: 3.8
How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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QUESTION: How many different values of y satisfy |y+3|=|8+y|+|4−y| ?

Each |y+3|, |8+y|, and |4−y| has a value of 0 or positive number.

For y>= -3, |y+3| is always less than |8+y|
--> (y+3) < (y+8)
--> 3 < 8
Hence, |y+3| is also always less than |8+y| + |4−y|

For y< -3, |y+3| is always less than |4-y|
--> -(y+3) < (4-y)
--> -3 < 4
Hence, |y+3| is also always less than |8+y| + |4−y|

As discussed, for any y value, |y+3| will never be equal to |8+y|+|4−y|

Originally posted by chondro48 on 03 Jul 2019, 22:05.
Last edited by chondro48 on 03 Jul 2019, 22:22, edited 1 time in total.
Manager  S
Joined: 24 Jan 2019
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Location: India
Concentration: Strategy, Finance
GMAT 1: 730 Q51 V38
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Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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This is a tricky question. First of we should understand that (Y+3), (8+Y) & (4-Y) will change signs at -3, -8 & +4 respectively. These 3 points are the minimum (| f(y)|=0) for given 3 modulus terms independently.

These 3 points will create 4 intervals on a number line as per following:

(1) Y< -8
(2) -8 <= Y < -3
(3) -3 <= Y < 4
(4) Y >= 4

Open all 3 modulus in each interval and solve for Y. Value which we get for Y in each interval doesn't belong to corresponding interval.

So, effectively we will have "0" values of Y which can satisfy given equation.

Senior Manager  G
Joined: 12 Sep 2017
Posts: 316
Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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Mahmoudfawzy83 wrote:
to find the possible values of y in $$|y+3|=|8+y|+|4−y|$$, there are 4 intervals to examine:
$$x≥4$$ --> y+3 = 8+y + y-4 --> $$y= -1$$ --> invalid because not within stated range
$$4>x ≥-3$$ --> y+3 = 8+y + 4-y --> $$y= 9$$ --> invalid because not within stated range
$$-3>x ≥-8$$ --> -y-3 = 8+y + 4-y --> $$y= -15$$ --> invalid because not within stated range
$$-8 ≥x$$ --> -y-3 = -8-y + 4-y --> $$y= -1$$ --> invalid because not within stated range

so there is acceptable value upon validating, so A

Hello Mahmoudfawzy83!

How do we know which term we have to change to neg depending the range?

Kind regards!
Director  V
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Re: How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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hi jfranciscocuencag
jfranciscocuencag wrote:
How do we know which term we have to change to neg depending the range?

By trying any value from the range, and see whether it will stay positive or negative.
lets take $$x>4$$
choose any number ... 5 or 100 .. the same will do:
when substituting y with 5, y+3 will be 8, so keep it--> +y+3
when substituting y with 5, 8+y will be 13, so keep it --> +8+y
when substituting y with 5, 4-y will be -1, so invert the signs --> -4+y

lets take $$-8 >x$$
choose any number ... -9 or -100 .. the same will do:
when substituting y with -9, y+3 will be -6, so invert the signs--> -y-3
when substituting y with -9, 8+y will be -1, so invert the signs --> -8-y
when substituting y with -9, 4-y will be 13, so keep it --> +4-y

It is tedious, but by practice, you will used to it. It is a very important step to use with every absolute value question.
Senior Manager  G
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How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?  [#permalink]

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choose any number ... 5 or 100 .. the same will do:
when substituting y with 5, y+3 will be 8, so keep it--> +y+3
when substituting y with 5, 8+y will be 13, so keep it --> +8+y
when substituting y with 5, 4-y will be -1, so invert the signs --> -4+y

lets take $$-8 >x$$
choose any number ... -9 or -100 .. the same will do:
when substituting y with -9, y+3 will be -6, so invert the signs--> -y-3
when substituting y with -9, 8+y will be -1, so invert the signs --> -8-y
when substituting y with -9, 4-y will be 13, so keep it --> +4-y

Mahmoudfawzy83

I have some doubt regarding the second example:

when substituting y with -9, y+3 will be -6, so invert the signs--> -y-3
when substituting y with -9, 8+y will be -1, so invert the signs --> -8-y

The numbers are -6 and -1 so they didn't change the sign, they are still neg. Why do we have to invert the sign here? How many different values of y satisfy |y + 3| = |8 + y| + |4 - y| ?   [#permalink] 04 Jul 2019, 18:19

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