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Re: How many factors does the integer 9999 have? [#permalink]
+1 for D :lol: , concept mentioned in GMATClub QUANT BOOK....do read to brushup basic and advance quant topics :idea:
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Re: How many factors does the integer 9999 have? [#permalink]
9999 = 3^2 * 11 * 101
and hence 2*2*3 = 12 distinct factors
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How many factors does the integer 9999 have? [#permalink]
We start with the prime factorization, as shown in the illustration.

Then, to find the number of factors, we add one to each of the powers and multply these additions.

So,

(2+1)*(1+1)*(1+1)
3*2*2
12

So, there are 12 factors in total.
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factorization.png
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Re: How many factors does the integer 9999 have? [#permalink]
Expert Reply
Mountain14 wrote:
How many factors does the integer 9999 have?

A. 6
B. 8
C. 10
D. 12
E. 15


Factorise 9999 = 3 * 3 * 11 * 101
= 3^2 * 11^1 * 101^1
Number of factors = (2+1)(1+1)(1+1)
= 3*2*2
=12
Hence option D.

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Re: How many factors does the integer 9999 have? [#permalink]
So 9 has 3 factors.

9 appears 4 times in the number.

4(3) = 12.

I checked this method with a few different numbers, all consiting of repeated integers less than 10 and it worked.

88

8 has 4 factors therefore 88 has 4(2)= 8.

Can anyone confirm that this works?

Posted from my mobile device
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How many factors does the integer 9999 have? [#permalink]
ak1802 wrote:
So 9 has 3 factors.

9 appears 4 times in the number.

4(3) = 12.

I checked this method with a few different numbers, all consiting of repeated integers less than 10 and it worked.

88

8 has 4 factors therefore 88 has 4(2)= 8.

Can anyone confirm that this works?

Posted from my mobile device


Interesting.....but didnt work for 777.
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Re: How many factors does the integer 9999 have? [#permalink]
I, for one, find it much easier to retain a formula if I understand it. Here's a video that goes over the logic behind the formula some of the responses are using:

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Re: How many factors does the integer 9999 have? [#permalink]
HarveyS wrote:
How many factors does the integer 9999 have?

A. 6
B. 8
C. 10
D. 12
E. 15


9999 = 3 * 3 * 11 * 101

Add 1 to powers of all prime factors and multiply:

(2+1) (1+1) (1+1)

3*2*2

12

(D)
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Re: How many factors does the integer 9999 have? [#permalink]
Expert Reply
HarveyS wrote:
How many factors does the integer 9999 have?

A. 6
B. 8
C. 10
D. 12
E. 15



Breaking 9999 into primes we have:

9999 = 9 x 1111 = 9 x 101 x 11 = 3^2 x 101^1 x 11^1

So the total number of factors is (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12.

Answer: D
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Re: How many factors does the integer 9999 have? [#permalink]
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Re: How many factors does the integer 9999 have? [#permalink]
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